Answer:
- Sn²⁺ ⇒ 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰
- Ti⁺ ⇒ 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁶ 4f¹⁴ 6s² 5d¹⁰
- As⁺³ ⇒ 1s² 2s² 2p⁶ 3s² 3p⁶ 4s²
Explanation:
The <em>electron configuration</em> indicates the way the electrons of an atom or ion are structured.<u> In the case of cations</u>, by knowing the electronic configuration of the atom (which is neutral), we can find out the cations' configuration by substracting <em>n</em> outermost electrons, where <em>n</em> is the charge of the cation.
Mg⁰ ⇒ [Ne] 3s² = 1s² 2s² 2p⁶ 3s². Thus
Mg⁺² ⇒ [Ne] = 1s² 2s² 2p⁶.
In a similar fashion, the answers are:
Sn²⁺ ⇒ 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰
K⁺ ⇒ 1s² 2s² 2p⁶ 3s² 3p⁶
Al³⁺ ⇒ 1s² 2s² 2p⁶
Ti⁺ ⇒ 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁶ 4f¹⁴ 6s² 5d¹⁰
As⁺³ ⇒ 1s² 2s² 2p⁶ 3s² 3p⁶ 4s²
The convection current is one of hot air rising, in this example, and then cooling and returning down. The rising air pushes the eagle up higher into the air. It just has to spread its wings and let the air push it into the air
Answer:
Shut yo musty dusty ah up zaddy
Explanation:
come here big mami
Disappointed by A and the B
Answer:
Part a: The IR spectrum is not sufficient due to the similar radical group presence in both product and reactants.
Part b: Mass Spectrum data is required in addition to the IR data for confirming the presence of recrystallized product.
Part c: The additional data is consistent with the expectations as the data is in support of that.
Explanation:
Part a
Acetanilide has a characteristic IR peak at around 3100-3200 cm^-1 (N-H Stretching) and 1500-1680 cm^-1 (C=O Stretching). Since a similar radical group (
) is present in the 4-bromoacetanilide, thus it is difficult to affirm the presence of the product solely on the basis of IR spectrum.
Part b
Mass Spectral data will affirm the presence of recrystallized product with certainty.
Part c
4-bromoacetanilide will have 
peak at two points (213 & 215) corresponding to the two Bromine isotopes (79 & 81).
Also parent peak at 171 (=43) will be in 49:51 due to presence of Bromine atoms.
