All categories

3 years ago

What's the ratio of atoms of each element in the compound ammonium monohydrogen phosphate (NH4)2HPO4?

Chemistry

1 answer:

GREYUIT [131]3 years ago

4 0

So there are 2 N, 9 H, 1 P and 4 O. so N:H:P:O is 2:9:1:4? i think

You might be interested in

a couple of pennies have a mas of 5.2 grams. Asuming that the pennies are 100% percent copper,how many moles of copper are the p

dangina [55]

Answer:

5.2g copper (Cu) => 0.082 moles copper (2 sig.figs.)

Explanation:

mole conversions:

grams to moles => divide by formula wt.

moles to grams => multiply by formula wt.

gas volumes to moles => divide volume by 22.4Liters/mole (STP conditions only)

This problem:

mass to moles => divide by formula wt.

mass = 5.2g = 5.2g/63.5g/mole = 0.082 moles copper (2 sig.figs.)

5 0

2 years ago

An atom of calcium contains 20 protons how many electrons does it have

harina [27]

20.

Atomic number is equivalent to its protons and electrons. :)

4 0

3 years ago

A standard 1.00 kg mass is to be cut from a bar of steel having an equilateral triangular cross section with sides equal to 2.50

Elden [556K]

Answer:

The section of the bar is 2.92 inches.

Explanation:

Mass of the steel cut ,m = 1.00 kg = 1000 g

Volume of the steel bar = V = Area × height

Height of the of the section of bar = h

Area of Equilateral triangular = $\frac{\sqrt{3}}{4}a^2$

a = 2.50 inches

Cross sectional area of the steel mass = A

$A=\frac{\sqrt{3}}{4}(2.50 inches)^2=2.71 inches^2$

$V = 2.71 inches^2\times h$

Density of the steel = d = $7.70 g/cm^3$

$1cm^3 = 0.0610237 inches^3$

$d=\frac{m}{v}$

$\frac{7.70 g}{0.0610237 inches^3}=\frac{ 1000 g}{2.71 inches^2\times h}$

$h=\frac{ 1000 g\times 0.0610237 inches^3}{2.71 inches^2\times 7.70 g}$

h = 2.92 inches

The section of the bar is 2.92 inches.

3 0

3 years ago

How many moles in 4.65 g of Helium?

Maru [420]

Answer:

4.65 g x 1 mol/4.0026 g/mol = 1.162 mol helium

Explanation:

7 0

3 years ago

What is the molarity of a 799 mL solution that contains 3.3 moles of NaNO3?

rusak2 [61]

Answer: I think It might be 1 M???

Explanation: Sorry I'm not in high school I put the wrong age

8 0

3 years ago