Answer:
5.2g copper (Cu) => 0.082 moles copper (2 sig.figs.)
Explanation:
mole conversions:
grams to moles => divide by formula wt.
moles to grams => multiply by formula wt.
gas volumes to moles => divide volume by 22.4Liters/mole (STP conditions only)
This problem:
mass to moles => divide by formula wt.
mass = 5.2g = 5.2g/63.5g/mole = 0.082 moles copper (2 sig.figs.)
20.
Atomic number is equivalent to its protons and electrons. :)
Answer:
The section of the bar is 2.92 inches.
Explanation:
Mass of the steel cut ,m = 1.00 kg = 1000 g
Volume of the steel bar = V = Area × height
Height of the of the section of bar = h
Area of Equilateral triangular = 
a = 2.50 inches
Cross sectional area of the steel mass = A


Density of the steel = d =




h = 2.92 inches
The section of the bar is 2.92 inches.
Answer:
4.65 g x 1 mol/4.0026 g/mol = 1.162 mol helium
Explanation:
Answer: I think It might be 1 M???
Explanation: Sorry I'm not in high school I put the wrong age