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slava [35]
3 years ago
11

What's the ratio of atoms of each element in the compound ammonium monohydrogen phosphate (NH4)2HPO4?

Chemistry
1 answer:
GREYUIT [131]3 years ago
4 0
So there are 2 N, 9 H, 1 P and 4 O. so N:H:P:O is 2:9:1:4? i think
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nata0808 [166]

Answer:

Explanation:

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6 0
2 years ago
Aluminum reacts with chlorine gas to produce aluminum chloride according to the following equation. Al + Cl2 → AlCl3 Which of th
anzhelika [568]
<h3><u>Answer</u>;</h3>

B. 3/2

<h3><u>  Explanation;</u></h3>

Balance the chemical equation

2Al + 3Cl2 → 2AlCl3

We want to convert moles of AlCl3 to moles of Cl2

The conversion factor is 2 mol AlCl3/3 mol Cl2.

We choose the one that makes the units cancel:

x mol AlCl3 x (3 mol Cl3)/(2mol AlCl3) = x mol Al

The fraction for the molar ratio is 3/2.

4 0
3 years ago
Read 2 more answers
Where do you place the symbols that represent the state of matter in an equation?
nexus9112 [7]
Subscript in a pair of brackets
5 0
3 years ago
Fluorine gas reacts with zinc (II) chloride →
dezoksy [38]

Answer:

Zinc Chloride + Difluorine -----> Zinc Fluoride + Dichlorine

Explanation:

ZnCl2 + F2 → ZnF2 + Cl2

5 0
3 years ago
if you mixed 72.9g hydrochloric acid(aq) with 150g silver acetate(aq), what would be the limiting reagent?​
horsena [70]

Answer:

                      Silver Acetate would be the Limiting Reagent.

Explanation:

                    The balance chemical equation for the given double displacement reaction is as;

                            HCl + AgC₂H₃O₂ → AgCl + HC₂H₃O₂

Step 1: <u>Calculate Moles of Starting Materials:</u>

Moles of HCl:

                      Moles  =  Mass / M.Mass

                      Moles  =  72.9 g / 36.46

                      Moles =  1.99 moles

Moles of AgC₂H₃O₂:

                      Moles  =  150 g / 166.91 g/mol

                      Moles  =  0.898 moles

Step 2: <u>Find out Limiting reagent as:</u>

According to balance chemical equation.

              1 mole of HCl reacts with  =  1 mole of AgC₂H₃O₂

So,

         1.99 moles of HCl will react with  =  X moles of AgC₂H₃O₂

Solving for X,

                     X =  1.99 mol × 1 mol / 1 mol

                     X =  1.99 mol of AgC₂H₃O₂

Hence, to completely consume 1.99 moles of Hydrochloric acid we will require 1.99 moles of Silver Acetate, But, we are provided with only 0.898 moles of Silver Acetate. This means Silver Acetate will consume first in the reaction therefore, it is the LIMITING REAGENT.

8 0
3 years ago
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