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2 years ago

Please help it's fricking urgent

Mathematics

2 answers:

Alenkasestr [34]2 years ago

6 0

Answer:

Kaden had $31

Ben had $41

Step-by-step explanation:

k = b - 10

k + 4 = (7/9)(b+ 4)

Substitute for k = b - 10

(b - 10) + 4 = (7/9)(b+ 4)

b - 6 = (7/9)(b+ 4)

multiply by 9 to clear the fraction

9b - 54 = 7(b + 4)

Distribute

9b - 54 = 7b + 28

subtract 7b from both sides

2b - 54 = 28

Add 54 to both sides

2b = 82

Divide both sides by 2

b = 41

k = b - 10

k = 31

Gwar [14]2 years ago

5 0

Answer:

Kaden had $17 at first

Step-by-step explanation:

Ben = x

Kaden = x - 10

x + 4

x - 10 + 4 = x -6

x - 6 = $\frac{7}{9}$ x

9(x - 6) = 7x

9x - 54 = 7x

2x = 54

x = 27

x - 10 = 27 - 10 = 17

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1 year ago

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Which of the following expressions is equivalent to a3 + b3?

lubasha [3.4K]

ANSWER
${a}^{3} + {b}^{3} = (a + b)( {a}^{2 } - ab + {b}^{2} )$

EXPLANATION

To find the expression that is equivalent to
${a}^{3} + {b}^{3}$
we must first expand
${(a + b)}^{3}$
Then we rearrange to find the required expression.

So let's get started.

${(a + b)}^{3} = (a + b) {(a + b)}^{2}$

We expand the parenthesis on the right hand side to get,

${(a + b)}^{3} = (a + b) ( {a}^{2} + 2ab + {b}^{2} )$

We expand again to obtain,

${(a + b)}^{3} = {a}^{3} + 3 {a}^{2}b + 3a {b}^{2} + {b}^{3}$

Let us group the cubed terms on the right hand side to get,

${(a + b)}^{3} = {a}^{3} + {b}^{3} + 3 {a}^{2}b + 3a {b}^{2}$

${(a + b)}^{3} = {a}^{3} + {b}^{3} + 3ab (a+ b)$

We make the cubed terms the subject,

${(a + b)}^{3} - 3ab (a+ b) = {a}^{3} + {b}^{3}$

We factor to get,

$(a + b)({(a + b)}^{2} - 3ab ) = {a}^{3} + {b}^{3}$

We expand the bracket on the left hand side to get,

$(a + b)( {a}^{2} + 2ab + {b}^{2} - 3ab ) = {a}^{3} + {b}^{3}$

We finally simplify to get,

$(a + b)( {a}^{2} - ab + {b}^{2} ) = {a}^{3} + {b}^{3}$

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