Answer:
equation form: x=-131/8y -31/40
Step-by-step explanation:
this is addition/elimination
Answer:
We can have two cases.
A quadratic function where the leading coefficient is larger than zero, in this case the arms of the graph will open up, and it will continue forever, so the maximum in this case is infinite.
A quadratic function where the leading coefficient is negative. In this case the arms of the graph will open down, then the maximum of the quadratic function coincides with the vertex of the function.
Where for a generic function:
y(x) = a*x^2 + b*x + c
The vertex is at:
x = -a/2b
and the maximum value is:
y(-a/2b)
Answer:
not sure if im right but this is my problem
3b=7
Step-by-step explanation:
Answer:
a = (v – u)/t
Step-by-step explanation:
We know,
v = u+ at
v-u=at
(v-u) /t=a
Answer:
True
Step-by-step explanation:
The year is typically divided into equal different lengths of time. There are, for example, quarters, which divide the year by 4, i. e., in 4 periods of 3 months each. Other example are semesters, in this case, the year is divided into 2 periods of 6 months each. Taking this into account, an interest calculated on a balance every three months is compounded quarterly.
