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Tju [1.3M]
3 years ago
8

A rock has a mass of 14,826 grams. what is the rocks mass in kilograms

Physics
2 answers:
pentagon [3]3 years ago
8 0

Answer: 14.826

<h3>Explanation: Because if you It also means <u>1 kilogram and 1000 grams are defined as being equal.</u></h3>

Mademuasel [1]3 years ago
7 0

Answer:

14.826 kg

Explanation:

move the decimal at the end over to the left 3 times

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As the spaceship travels upward in the sky, some of its kinetic energy will be lost to the universe due to ?
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Friction !!!

Explanation:

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Bart stole a watermelon and ran 5,000 feet from the cops and they chase lasted 0.1 hours how fast was Bart running in miles per
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I am not as sure but I think it is 9.469 miles
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When you put a pot of water on the stove, the stove transfers thermal energy to the water. As the water gains large
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It releases some of the energy into the atmosphere as hot steam.

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When a mass M hangs from a vertical wire of length L, waves travel on this wire with a speed V. What will be the speed of these
Zigmanuir [339]

Answer:

a)  v = 0.7071 v₀, b) v= v₀, c)  v = 0.577 v₀, d)   v = 1.41 v₀, e)  v = 0.447 v₀

Explanation:

The speed of a wave along an eta string given by the expression

          v = \sqrt{ \frac{T}{ \mu } }

where T is the tension of the string and μ is linear density

a) the mass of the cable is double

          m = 2m₀

let's find the new linear density

          μ = m / l

iinitial density

          μ₀ = m₀ / l

final density

          μ = 2m₀ / lo

          μ = 2 μ₀

we substitute in the equation for the velocity

initial            v₀ = \sqrt{ \frac{T_o}{ \mu_o} }

with the new dough

                    v = \sqrt{ \frac{T_o}{ 2 \mu_o} }

                    v = 1 /√2  \sqrt{ \frac{T_o}{ \mu_o} }

                    v = 1 /√2 v₀

                    v = 0.7071 v₀

b) we double the length of the cable

If the cable also increases its mass, the relationship is maintained

              μ = μ₀

   in this case the speed does not change

c) the cable l = l₀ and m = 3m₀

we look for the density

           μ = 3m₀ / l₀

           μ = 3 m₀/l₀

           μ = 3 μ₀

            v = \sqrt{ \frac{T_o}{ 3 \mu_o} }

            v = 1 /√3  v₀

            v = 0.577 v₀

d) l = 2l₀

            μ = m₀ / 2l₀

            μ = μ₀/ 2

           v = \sqrt{ \frac{T_o}{ \frac{ \mu_o}{2} } }

           v = √2 v₀

            v = 1.41 v₀

e) m = 10m₀ and l = 2l₀

we look for the density

             μ = 10 m₀/2l₀

             μ = 5 μ₀

we look for speed

             v = \sqrt{ \frac{T_o}{5 \mu_o} }

             v = 1 /√5  v₀

             v = 0.447 v₀

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3 years ago
An object is thrown into the air at 60m/s, straight up. What is its velocity at the highest point?
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Explanation:

Whenever an object is at its highest point, the velocity and acceleration of the object is zero.

6 0
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