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Monica [59]
3 years ago
7

A piece of wood that floats on water has a mass of 0.0175 kg. A lead sinker is tied to the wood, and the apparent mass with the

wood in air and the lead sinker submerged in water is 0.0765 kg. The apparent mass with both the wood and the sinker both submerged in water is 0.0452 kg. What is the SG of the wood
Physics
1 answer:
Georgia [21]3 years ago
5 0

Answer:

The specific gravity of the wood is 1.56

Explanation:

Given;

mass of the wood in water, M_w_{H_2O} = 0.0175 kg

apparent mass of the wood and lead sinker submerged in water, M_w_{(air)} + M_s_{H_2O} = 0.0765 kg

apparent mass with both the wood and the sinker both submerged in water, M_w_{H_2O}  + M_s_{H_2O} = 0.0452 \ kg

Mass of the lead sinker alone submerged in water;

M_w_{H_2O} + M_s_{H_2O} = 0.0452 \ kg\\\\0.0175 \ kg + M_s_{H_2O} = 0.0452 \ kg\\\\M_s_{H_2O} = 0.0452 \ kg - 0.0175 \ kg\\\\M_s_{H_2O} = 0.0277 \ kg

Mass of the wood in the air;

M_w_{(air)} + M_s_{H_2O} = 0.0765 \ kg\\\\M_w_{(air)}  + 0.0277 \ kg = 0.0765 \ kg\\\\M_w_{(air)}  = 0.0765 \ kg - 0.0277 \ kg\\\\M_w_{(air)}  = 0.0488 \ kg

Mass of water is calculated as follows;

M_w_{(air)} - M_w_{H_2O} = M_{H_2O}\\\\0.0488 \ kg - 0.0175 \ kg = M_{H_2O}\\\\0.0313 \ kg = M_{H_2O}

The specific gravity of the wood is calculated as follows;

Specific \ gravity\  (S.G) \ of \ wood = \frac{mass \ of \ wood\ in \ air }{mass \ of \  water} \\\\Specific \ gravity\  (S.G) \ of \ wood = \frac{0.0488}{0.0313} \\\\Specific \ gravity\  (S.G) \ of \ wood = 1.559 = 1.56

Therefore, the specific gravity of the wood is 1.56

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Delvig [45]

Answer:

X component of force is 60.62 N.

Y component of force is 35 N.

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Magnitude of normal force is 210 N.

Explanation:

Given:

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Mass of the dog is, m=25\ kg

Angle of inclination is, \theta =30°

Acceleration due to gravity is, g=9.8\ m/s^2

The free body diagram of the dog is shown below.

The X and Y components of force of pull is given as:

F_X=F\cos \theta=(70)\cos (30)=60.62\ N\\F_Y=F\sin \theta=(70)\sin(30)=35\ N

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Force of gravity on the dog is the product of its mass and acceleration due to gravity. Thus,

F_g=mg=25\times 9.8=245\ N

Therefore, the force of gravity on the dog is 245 N.

Now, consider the motion in the vertical direction of the dog. As there is no motion in the vertical direction, the net force along the Y direction is 0. In other words, the total Upward force is equal to the total downward force.

From the free body diagram,

N+F_Y=mg\\N=mg-F_Y\\N=245-35=210\ N

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3 years ago
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Answer:

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Answer:

Fr=12544N

Explanation:

1. Find the equation of eht maximal friction force:

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Answer:

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The total distance covered by the train during the entire journey is the area of the speed-time graph.

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As velocity is in m/s and time is in s so the unit of area is m

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Answer:

T is less than or equal to 19 N

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