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3 years ago

An object is thrown into the air at 60m/s, straight up. What is its velocity at the highest point?

Physics

1 answer:

Cloud [144]3 years ago

6 0

Explanation:

Whenever an object is at its highest point, the velocity and acceleration of the object is zero.

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One molecule of bromine (Br2) and two molecules of potassium chloride (KCI) combine in a reaction. How many atoms are in the pro

Liula [17]

In the reaction between 1 molecule of bromine and 2 molecules of potassium chloride, there are six atoms in the products.

Let's consider the balanced equation for the reaction between 1 molecule of bromine and 2 molecules of potassium chloride. This is a single replacement reaction.

Br₂ + 2 KCl ⇒ 2 KBr + Cl₂

We obtain as products, 2 molecules of potassium bromide and 1 molecule of chlorine.

1 molecule of KBr has 2 atoms, so 2 molecules contribute with 4 atoms.
1 molecule of Cl₂ has 2 atoms.
The 4 atoms from KBr and the 2 atoms from Cl₂ make a total of 6 atoms.

In the reaction between 1 molecule of bromine and 2 molecules of potassium chloride, there are six atoms in the products.

Learn more: brainly.com/question/21850455

5 0

3 years ago

Read 2 more answers

A rugby player sits on a scrum machine that weighs 200 Newtons. Given that the coefficient of static friction is 0.67, the coeff

Trava [24]

a. 850 N is the minimum force needed to get the machine/player system moving, which means this is the maximum magnitude of static friction between the system and the surface they stand on.

By Newton's second law, at the moment right before the system starts to move,

• net horizontal force

∑ F[h] = F[push] - F[s. friction] = 0

• net vertical force

∑ F[v] = F[normal] - F[weight] = 0

and we have

F[s. friction] = µ[s] F[normal]

It follows that

F[weight] = F[normal] = (850 N) / (0.67) = 1268.66 N

where F[weight] is the combined weight of the player and machine. We're given the machine's weight is 200 N, so the player weighs 1068.66 N and hence has a mass of

(1068.66 N) / g ≈ 110 kg

b. To keep the system moving at a constant speed, the second-law equations from part (a) change only slightly to

∑ F[h] = F[push] - F[k. friction] = 0

∑ F[v] = F[normal] - F[weight] = 0

so that

F[k. friction] = µ[k] F[normal] = 0.56 (1268.66 N) = 710.45 N

and so the minimum force needed to keep the system moving is

F[push] = 710.45 N ≈ 710 N

4 0

2 years ago

PICTURE ABOVE !

Rom4ik [11]

Answer:

she should ve the one handing out the cookies each day, to make sure each child gets only one cookie a day.

3 0

4 years ago

A current of 12 amps is measured in a circuit with a total resistance of 9.0 ohms. What is the size of the voltage source that s

Serjik [45]

Data:
i (current) = 12 A
R (resistance) = 9.0 Ω
V (voltage) = ? (volts)

Formula:
$V = R*i$

Solving:
$V = R*i$
$V = 9.0*12$
$\boxed{\boxed{V = 108\:volts}}\end{array}}\qquad\quad\checkmark$

6 0

3 years ago

What is the pressure exerted on three floor by a 10.000N crate if the bottom of the crate has the dimensions of 1/2m by 4m

Fantom [35]

Answer:

fine the area then devide force by area

Explanation:

10000/(0.5*4)= 5000 pa

6 0

3 years ago