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irga5000 [103]
2 years ago
13

Which planet has the closest gravitational pull to earth

Physics
2 answers:
Firdavs [7]2 years ago
4 0

Answer:

venus

Explanation:

VARVARA [1.3K]2 years ago
4 0
Jupiter exerts the greatest gravitational pull on the Earth. However, this pull is only 0.0000068 times the gravitational pull of the moon. Jupiter’s gravitational pull at its surface is 2.36 times that of Earth.
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What is the horizontal component of a ball thrown at a 27 degree angle at 16 m/s?
Airida [17]

Answer:

14.25 m/s

Explanation:

In this problem, we need to find the horizontal component of a ball thrown at a 27 degree angle at 16 m/s.

It can be given by :

v_x=v\cos\theta\\\\=16\times \cos(27)\\\\=14.25\ m/s

So, the horizontal component of the ball is 14.25 m/s.

6 0
3 years ago
An Earth satellite is in a circular orbit at an altitude of 500 km.
Dafna1 [17]

Answer:

Speed Unchanged.

Explanation:

As work is defined as a product of force over a distance. If the distance in altitude is constant = 500km, there's 0 change in distance and force, no work would be done by the gravitational force.

Since potential energy of the satellite is unchanged, unless there's additional internal energy source, the kinetic energy would remain unchanged, so would its speed.

8 0
3 years ago
What principle of light’s behavior can be used to make a far away object appear closer and also make a small object appear large
4vir4ik [10]
It would be refraction
3 0
3 years ago
Read 2 more answers
How many joules of work are done against a truck when a force of 50 N pushes it 1 kilometer away
ELEN [110]

Answer:

Work = 50,000 J

Explanation:

Work = force * distance

Given that,

  • force = 50N
  • Distance = 1km = 1000m

Work = 50 * 1000

Work = 50,000 J

8 0
2 years ago
An ideal refrigerator does 130. 0 j of work to remove 780. 0 j of heat from its cold compartment during each cycle. what is the
zheka24 [161]

The refrigerator's coefficient of performance is 6.

The heat extracted from the cold reservoir Q cold (i.e., inside a refrigerator) divided by the work W required to remove the heat is known as the coefficient of performance, or COP, of a refrigerator (i.e., the work done by the compressor). The required inside temperature and the outside temperature have a significant impact on the COP.

As the inside temperature of the refrigerator decreases, its coefficient of performance decreases. The coefficient of performance (COP) of refrigeration is always more than 1.

The heat produced in the cold compartment, H = 780.0 J

Work done in ideal refrigerator, W = 130.0 J

Refrigerator's coefficient of performance = H/W

                                                                     = 780/130

                                                                     = 6

Therefore, the refrigerator's coefficient of performance is 6.

Energy conservation requires the exhaust heat to be = 780 + 130

                                                                                          = 910 J

Learn more about  coefficient here:

brainly.com/question/18915846

#SPJ4

5 0
2 years ago
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