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3 years ago

If a substance has a large mass and a small volume how dense is it

Chemistry

1 answer:

Over [174]3 years ago

4 0

Answer:

Very dense.

Explanation:

Conceptually, you are taking a large amount of atoms and putting them into a small container. This means the spaces between atoms has to be smaller and the substance is more dense. (see image)

Mathematically, the equation for density is mass divided by volume ( $Density=\frac{m}{v}$ ). If you divide a big number by a small number, you still have a pretty big number (ex 4/2=2 versus 6/1=6)

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What mass of nitrogen Dioxide, NO2, would be produced by the decomposition of 75.0g of copper (II) nitrate?

-Dominant- [34]

When copper(II) nitrate Cu(NO3)2 decomposition, the final products will determine by temperature. But the ratio of Cu(NO3)2 and NO2 is constant: 1:2. So mole number of 75 g is 0.4 mol. So NO2 is 0.8 mol and is 36.8 g.

7 0

2 years ago

A sealed container can hold

svp [43]

0.216 moles of gas can the container hold if a sealed container can hold 0.325 L of gas at 1.00 atm and 293 K.

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.

Given data:

R = gas constant = 0.08206 L.atm / mol K

T = temperature, Kelvin

V=5 L

P = 1.05 atm

T = 296 K

Putting value in the given equation:

$\frac{PV}{RT}=n$

$n= \frac{1.05 atm\; X \;5 L}{ 0.08206 L.atm / mol K X 296 K}$

Moles = 0.216 moles

Hence, 0.216 moles of gas can the container hold if a sealed container can hold 0.325 L of gas at 1.00 atm and 293 K.

Learn more about the ideal gas here:

brainly.com/question/27691721

#SPJ1

6 0

2 years ago

Ñspent fuelî that can no longer be used to create energy. nuclear waste ?

svetoff [14.1K]

Spent fuel that can no longer be used to create energy is waste.

6 0

3 years ago

Grams of cl in 38g of cf3cl

Lerok [7]

Answer:

114 grams

Explanation:

3chlorines per compound*38grams=114

8 0

3 years ago

HURRY PLEASE

katrin2010 [14]

Answers:

Question 1:

The diagram for gallium will have flat, horizontal lines at 30 and 2204 °C.

Questoin 2:

The diagram for methane will have a diagonal line representing the liquid phase between -183°C and -162°C.

Question 3:

For gold, the boiling point corresponds to the y-value at 2856 °C of the top horizontal line

Question 4.

For nitrogen, the line at -210°C will be flat, which represents the change from a solid to a liquid

Explanations:

Question 1:

The diagram for gallium will have flat, horizontal lines at 30 and 2204 °C.

The table shows that the melting point of gallium is 30°C and its boiling point is 2204°C.

Melting point is the temperature at which the substace changes its state from solid to liquid. During that change, the temperature of the substance does not change, because the heat supplied is used to accomplish the phase change. So, the temperature is constant and that means that portion of the diagram is flat.

The same is valid during boiling: the temperature remains constant while the substance is passing from liquid to gas at the boiling point.

Questoin 2:

The diagram for methane will have a diagonal line representing the liquid phase between -183°C and -162°C.

Between the melting (-183°C) and boiling (-162°C) points of methane, its temperature will increase more or less linearly, which is represented with a diagonal (slant) line between those points. During this interval the heat is used to increase the temperature and no phase of change happens.

Question 3:

For gold, the boiling point corresponds to the y-value at 2856 °C of the top horizontal line

The table shows that the boiling point of gold is 2,856°C.

In a temperature-vs.-time diagram the temperature is represented on the vertical axis (y-value) and the time is represented on the horizontal axis.

Since, the temperature of the substance does not change during boiling, the line during the time that this change of phase is happening is flat. And since this temperatue is higher than the melting temperature, this is the top horizontal line in the diagram.

Question 4.

For nitrogen, the line at -210°C will be flat, which represents the change from a solid to a liquid

The table shows that the melting point of nitrogen is -210°C, that means that the temperature will remain constant at -210°C while the substance is absorbing heat to pass from solid to liquid.

In conclusion, you must remember that all the phase changes, melting (from solid to liquid), freezing (from liquid to solid), boilng (from liquid to gas), and condensing (from gas to liquid) happens at constant temperature, and so the temperature - vs. - time diagrams show flat lines (constant y-values) during those intervals of time.

4 0

2 years ago

Read 2 more answers