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Alex
3 years ago
13

What mass of nitrogen Dioxide, NO2, would be produced by the decomposition of 75.0g of copper (II) nitrate?

Chemistry
1 answer:
-Dominant- [34]3 years ago
7 0
When copper(II) nitrate Cu(NO3)2 decomposition, the final products will determine by temperature. But the ratio of Cu(NO3)2 and NO2 is constant: 1:2. So mole number of 75 g is 0.4 mol. So NO2 is 0.8 mol and is 36.8 g.
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NaCl has a mc020-1.jpgHfus = 30.2 kJ/mol. What is the mass of a sample of NaCl that needs 732.6 kJ of heat to melt completely?
lilavasa [31]

Answer: The mass of the sample will be 1417.7 grams.

Explanation:

We are given:

\Delta H_{fusion}=30.2kJ/mol

This means that 1 mole of NaCl has an enthalpy of fusion of 30.2 kJ

1 mole of NaCl has a mass of 58.44 grams.

So, 30.2 kJ of heat is require for a mass 58.44 grams of NaCl

So, 732.6 kJ of heat will be required for = \frac{58.44g}{30.2kJ}\times 732.6 kJ = 1417.65 grams of NaCl.

Hence, the mass of NaCl sample will be 1417.7 grams.

5 0
3 years ago
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The table shows the charge on three unknown subatomic particles.
brilliants [131]

Answer:

B. only particle Z

Explanation:

In the case of subatomic particles, those positive and neutral are located in the nucleus, and those with a negative charge on the outside.

8 0
4 years ago
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Answer and work for this problem
MArishka [77]
We can write the balanced equation for the synthesis reaction as 
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We use the molar masses of hydrogen chloride gas HCl and hydrogen gas H2 to calculate for the mass of hydrogen gas H2 needed:
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We also use the molar masses of hydrogen chloride gas HCl and chlorine gas CL2 to calculate for the mass of hydrogen gas H2:
     mass of CL2 = 146.4 g HCl *(1 mol HCl / 36.46 g HCl) * (1 mol Cl2 / 2 mol HCl) *
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Therefore, we need 4.056 grams of hydrogen gas and 142.4 grams of chlorine gas to produce 146.4 grams of hydrogen chloride gas.
6 0
3 years ago
Mercury thermometers work because mercury ____ when it is warmed
kap26 [50]
Mercury expands when it is heated. This process is called thermal expansion.
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3 years ago
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Sergeeva-Olga [200]

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4 0
3 years ago
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