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Alex
3 years ago
13

What mass of nitrogen Dioxide, NO2, would be produced by the decomposition of 75.0g of copper (II) nitrate?

Chemistry
1 answer:
-Dominant- [34]3 years ago
7 0
When copper(II) nitrate Cu(NO3)2 decomposition, the final products will determine by temperature. But the ratio of Cu(NO3)2 and NO2 is constant: 1:2. So mole number of 75 g is 0.4 mol. So NO2 is 0.8 mol and is 36.8 g.
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There are a lot of empty space between the particles
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3 years ago
1.- Ilumina de amarillo los verbos en pretérito y de verde los verbos en copretérito.
ivanzaharov [21]

Answer:

Pretérito (Pretérito perfecto):

<em>estiró, sudó, peleó, compartí</em>

Copretérito (Pretérito imperfecto):

<em>saludaba, pedias, leia, compraba, barrias, cargaba, estrenabas, escribian</em>

Explanation:

Los verbos en pretérito, también llamado pretérito perfecto, son los siguientes:

<em>estiró, sudó, peleó, compartí</em>

Como se aprecia, los verbos conjugados en pretérito perfecto terminan la última sílaba en vocal con acento, es decir, <em>-á</em>, <em>-é</em>, <em>-í</em> u <em>-ó</em>.

Los verbos en copretérito, también llamado pretérito imperfecto, son los siguientes:

<em>saludaba, pedias, leia, compraba, barrias, cargaba, estrenabas, escribian</em>

Como se aprecia, los verbos conjugados en pretérito imperfecto terminan la última sílaba en <em>-ía</em>, <em>ías</em>, <em>-ían</em>, <em>-aba</em>, <em>-abas</em> o <em>-aban</em>.  

3 0
3 years ago
The hormone thyroxine is secreted by the thyroid gland and has the formula: C15H17NO4I4. How many milligrams of Iodine can be ex
Ede4ka [16]
I'm pretty sure it's 9726 milligrams of iodine. Hope this helps.
6 0
3 years ago
Read 2 more answers
A red car and a blue car collide. What would be an example of Locard's exchange principle in this situation?
Lelu [443]

Answer:

The blue car left paint on the red car

Explanation:

8 0
3 years ago
In an experiment, a student needs 250.0 mL of a 0.100 M copper (II) chloride solution. A stock solution of 2.00 M copper (II) ch
LekaFEV [45]

Answer : The volume of stock solution needed are, 12.5 mL

Explanation :

Formula used :

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the initial molarity and volume of copper (II) chloride.

M_2\text{ and }V_2 are the final molarity and volume of stock solution of copper (II) chloride.

We are given:

M_1=0.100M\\V_1=250.0mL\\M_2=2.00M\\V_2=?

Putting values in above equation, we get:

0.100M\times 250.0mL=2.00M\times V_2\\\\V_2=12.5mL

Hence, the volume of stock solution needed are, 12.5 mL

8 0
3 years ago
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