Characteristic properties can be used to describe and identify the substances, while non-characteristic properties, although can be used to describe the substances, cannot be used to identify them.
Temperature, mass, color, shape and volume are examples of non-characteristic properties.
Density, boiling point, melting point, chemical reactivity are examples of characteristic properties.
List of the properties observed by the scientist:
-----------------------------------------------------------------
Property Type of property
----------------------------------------------------------------
Volume: 5 ml non-characteristic
----------------------------------------------------------------
Color: blue non-characteristic
----------------------------------------------------------------
State: liquid characteristic
------------------------------------------------------------
density: 1.2 g/cm characteristic
------------------------------------------------------------
Reaction: reacts with CO2 characteristic
----------------------------------------------------------
A scale and a ruler. The scale to measure the mass, and a ruler to measure the volume.
99.9224 % of the acid is not ionized.
____HA + H₂O ⇌ A⁻ + H₃O⁺
I: ___<em>c</em> ________0 ____0
C: _-α<em>c</em> _______+α<em>c</em> __+α<em>c
</em>
E: <em>c</em>(1-α) _______α<em>c</em> ___α<em>c
</em>
pH = 4.110
[H₃O⁺] = α<em>c</em> = 10^(-4.110) mol/L = 7.76 × 10⁻⁵ mol/L
α = 7.76 × 10⁻⁵
1 – α = 1 - 7.76 × 10⁻⁵ = 0.999 224 = 99.9224 %
126 grams of H2O is formed.
Explanation:
Data given:
volume of the gas = 88 Liters
pressure = 720 mm Hg or 0.947 atm
temperature T = 22 Degrees or 295.15 K
R = 0.08021 atm L/mole K
n =?
The formula is used is of ideal gas law to know the number of moles of CH4 undergoing combustion.
PV = nRT
n = 
putting the values in the equation
= 0.947 X 88/ 0.08021 X 295.15
n = 3.5 moles
balanced reaction for combustion of methane
CH4 + O2 ⇒ CO2 + 2H20
1 mole of CH4 undergoes combustion to form 2 moles of water
3.5 moles will give x moles of water
2/1 = x/3.5
x = 7 moles of water (atomic mass of water = 18 gram/mole)
mass = atomic mass x number of moles
mass = 18 x 7
=126 grams of water is formed.
