All categories

2 years ago

HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP

Chemistry

2 answers:

Trava [24]2 years ago

4 0

Answer:

b..................

kipiarov [429]2 years ago

3 0

Answer:

Box A

Explanation:

Density is determined by how close together particles are. It is visually clear that Box A is tighter compacted. (^-^)

You might be interested in

What is the density of a block of marble that occupies 277 cm3 and has a mass of 928 g? Answer in units of g/cm3 .

Evgesh-ka [11]

$V=277cm^{3}\\
m=928g\\\\
d=\frac{m}{V}=\frac{928g}{277cm^{3}}\approx3,35\frac{g}{cm^{3}}$

8 0

3 years ago

Scientists want to eventually collect data from the surface of Venus. Which is a technology that could be used to collect sample

ivanzaharov [21]

Answer:

Explanation:

Because im smart

6 0

3 years ago

Balance the folowing equation.<br> S + 02<br> ws<br> SO:

Rzqust [24]

Answer:

s+o2=so2

Explanation:

i hope it will help u

6 0

3 years ago

5. A beam of photons with a minimum energy of 222 kJ/mol can eject electrons from a potassium surface. Estimate the range of wav

torisob [31]

Answer: The range of wavelengths of light that can be used to cause given phenomenon is $8.953 \times 10^{21} m$ .

Explanation:

Given: 222 kJ/mol (1 kJ = 1000 J) = 222000 J

Formula used is as follows.

$E = \frac{hc}{\lambda}$

where,

E = energy

h = Planck's constant = $6.625 \times 10^{-25} Js$

c = speed of light = $3 \times 10^{8} m/s$

Substitute the values into above formula as follows.

$E = \frac{hc}{\lambda}\\222000 J = \frac{6.625 \times 10^{-34}Js \times 3 \times 10^{8} m/s}{\lambda}\\\lambda = 8.953 \times 10^{21} m$

Thus, we can conclude that the range of wavelengths of light that can be used to cause given phenomenon is $8.953 \times 10^{21} m$ .

7 0

3 years ago

The most common cooling mechanism for cloud formation is ________.

KatRina [158]

The answer is "Rising and expanding air or atmosphere cooling".
To form a cloud the air must be cooled to the temperature of dew point. when there is expansion of air, it cools to the dew point and thus the formation of cloud happens. This process is very common and used for the formation of clouds.

8 0

3 years ago