Explanation:
More quickly a reactant will disappear, the more quickly it will result in the formation of products. This means that consumption or disappearance of reactants determines the rate of a reaction because only then products will be formed.
Thus, we can conclude that measuring how quickly a reactant disappears is one way to measure the rate of the reaction.
In this question, XB3(aq) is an ionic compound which will have the releasing of 3 B⁻ ions ions in water for every molecule of XB3 that dissolves.
XB3(s) --> X+(aq) + 3 B⁻(aq)
[B⁻] = 0.22 mol XB3/1L × 3 mol B⁻ / 1 mol XB3 = 0.66 M
The answer to this question is [B⁻] = 0.66 M
Answer:
lungs and blood vessels, airway
Explanation:
because the respiratory system are a system that helps people breate. the lungs breathe in oxygen and then breathe out carbon dioxide. the blood vessels carries the oxygen into the body to other part of the system in the body that needed oxygen to make glucose.
Answer:
268.75 K
Explanation:
We are given;
- Initial pressure, P1 as 600 torr
- Initial temperature, T1 as 215 K
- New pressure, P2 as 750 torr
We are required to determine the new temperature, T2.
To solve this question we are going to use the pressure law of gases.
According to pressure law, the temperature of a fixed mass of a gas and its pressure are directly proportional at constant volume.
That is;
Pα T
Therefore;

Thus,



Therefore, the new temperature is 268.75 K
Answer:
The metal has a heat capacity of 0.385 J/g°C
This metal is copper.
Explanation:
<u>Step 1</u>: Data given
Mass of the metal = 21 grams
Volume of water = 100 mL
⇒ mass of water = density * volume = 1g/mL * 100 mL = 100 grams
Initial temperature of metal = 122.5 °C
Initial temperature of water = 17°C
Final temperature of water and the metal = 19 °C
Heat capacity of water = 4.184 J/g°C
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<u>Step 2: </u>Calculate the specific heat capacity
Heat lost by the metal = heat won by water
Qmetal = -Qwater
Q = m*c*ΔT
m(metal) * c(metal) * ΔT(metal) = - m(water) * c(water) * ΔT(water)
21 grams * c(metal) *(19-122.5) = -100 * 4.184 * (19-17)
-2173.5 *c(metal) = -836.8
c(metal) = 0.385 J/g°C
The metal has a heat capacity of 0.385 J/g°C
This metal is copper.