Answer: Between the alveoli and a network of tiny blood vessels called capillaries, which are located in the walls of the alveoli.
Answer:
abiotic things
abiotic things aren't living
Explanation:
(A) As we know that carbonic acid (
) and Sodium bicarbonate (
) forms an acidic buffer.
Therefore, pH of an acidic buffer is given by Hendeerson-Hasselbalch equation as follows.
pH = ![pK_{a} + log(\frac{[Salt]}{[Acid]})](https://tex.z-dn.net/?f=pK_%7Ba%7D%20%2B%20log%28%5Cfrac%7B%5BSalt%5D%7D%7B%5BAcid%5D%7D%29)
........... (1)
So mathematically, if [Salt] = [Acid] then ![\frac{[Salt]}{[Acid]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BSalt%5D%7D%7B%5BAcid%5D%7D)
= 1
.
And, ![log (\frac{[Salt]}{[Acid]})](https://tex.z-dn.net/?f=log%20%28%5Cfrac%7B%5BSalt%5D%7D%7B%5BAcid%5D%7D%29)
= 0
Therefore, equation (1) gives us the following.
pH = 
(when acid and salt are equal in concentration)
Hence, of (carbonic acid) is 6.35.
And, with this we have following results.
In (A) and (D) we have the case \frac{[NaHCO_{3}]}{[H_{2}CO_{3}]}[/tex] i.e. [Salt] = [Acid].
Hence, for the cases pH = = 6.35.
(B) ![[NaHCO_{3}]](https://tex.z-dn.net/?f=%5BNaHCO_%7B3%7D%5D)
= 0.045 M and, ![[H_{2}CO_{3}]](https://tex.z-dn.net/?f=%5BH_%7B2%7DCO_%7B3%7D%5D)
= 0.45 M
Hence, pH = ![6.35 + log([NaHCO_{3}][[H_{2}CO_{3}])](https://tex.z-dn.net/?f=6.35%20%2B%20log%28%5BNaHCO_%7B3%7D%5D%5B%5BH_%7B2%7DCO_%7B3%7D%5D%29)
= 
= 6.35 + (-1)
= 5.35
Therefore, it means that this buffer will be most suitable buffer as it has pH on acidic side and addition of slight excess base will not affect much of its pH value.
(C) = 0.45 M
= 0.045 M
So, pH = ![6.35 + log(\frac{[NaHCO_{3}]}{[H_{2}CO_{3}]})](https://tex.z-dn.net/?f=6.35%20%2B%20log%28%5Cfrac%7B%5BNaHCO_%7B3%7D%5D%7D%7B%5BH_%7B2%7DCO_%7B3%7D%5D%7D%29)
= 
= 6.35 + (+1)
= 7.35
This means that pH on Basic side makes it no more acidic buffer.
Answer: i think its A
step by step explanation:
In an average mass, each entry has equal weight. In a weighted average, we multiply each entry by a number representing its relative importance.
Assume that your class consists of 15 girls and 5 boys. Each girl has a mass of 54 kg, and each boy has a mass of 62 kg.
<em>Average mass</em> = (girl + boy)/2 = (54 kg + 62 kg)/2 = <em>58 kg</em>
<em>Weighted average (Method 1)
</em>
Use the <em>numbers of each</em> gender (15 girls + 5 boys)
,
Weighted average = (15×54 kg + 5×62 kg)/20 = (810 kg + 310 kg)/20
= 1120 kg/20 = <em>56 kg</em>.
If you put all the students on one giant balance, their total mass would be
1120 kg and the average mass of a student would be <em>56 kg.
</em>
<em>Weighted average (Method 2)
</em>
Use the <em>relative percentages</em> of each gender (75 % girls and 25 % boys).
Weighted average = 0.75×54 kg + 0.25×62 kg = 40.5 kg + 15.5 kg = <em>56 kg</em>
Each girl contributes 40.5 kg and each boy contributes 15.5 kg to the <em>weighted average</em> mass of a student.
