The average atomic mass of iron is the sum of the products of the percentage abundance and masses of the isotopes. That is,
average atomic mass = 0.0582 x 53.940 amu + 0.9166 x 55.935 amu + 0.0219 x 56.935 amu + 0.0033 x 57.933 amu = 55.847 amu
Thus, the average atomic mass of iron is approximately 55.847 amu.
Answer:
0.047 moles
Explanation:
From the question,
Applying
PV = nRT............. Equation 1
Where P = Pressure of CH₄ gas, V = Volume of CH₄ gas, n = number of moles of CH₄ gas, R = Molar gas constant.
make n the subject of the equation
n = PV/RT............. Equation 2
Given: P = 660 torr = (660×0.00131579) atm = 0.868 atm, V = 1300 mL = (1300/1000) L = 1.3 L, T = 20 °C = (20+273) K = 293 K
Constant: R = 0.082 atm.dm³/K.mol
Substitute these values into equation 2
n = (0.868×1.3)/(0.082×293)
n = 1.1284/24.026
n = 0.047 mole
Answer:
15912 × 10∧-19 KJ
Explanation:
Given data;
frequency of photon = 2.4 × 10^18 1/s.
Planck's constant = 6.63 × 10∧-34 j.s
Energy = ?
Formula:
E = h × ν
E = 6.63 × 10∧-34 j.s × 2.4 × 10^18 1/s
E= 15.912 × 10∧-16 j
now we will convert the joule into kilo joule,
E = 15.912 × 10∧-16 j /1000 = 15.912 × 10∧-19 KJ
Answer:
Chemical properties can be recognized only when substances react or do not react chemically with one another, that is, when they undergo a change in composition. A chemical property of one substance usually involves its ability to react or not react with another specific substance.
The temp is 0.002448 of the equation
