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Korvikt [17]
3 years ago
10

this is my 5th time waisting my points for this question because I could fail my final and I am not getting any answers so can s

omeone give me some attention here!!!

Physics
1 answer:
Neko [114]3 years ago
8 0

Answer:

<em>The person needs to apply 25 N to balance the seesaw</em>

Explanation:

<u>Moment</u>

The moment of a force is a measure of its tendency to cause a body to rotate about a specific point or axis.

The moment M of a force F located at a distance x from the axis of rotation is calculated as follows:

M = F.x

The image shows a moment of M=100 N.m is needed to be applied to balance the seesaw. It can also be noted that the distance to the pivot is x=4 m

To calculate the force needed to balance the seesaw, we solve for F:

\displaystyle F=\frac{M}{x}

\displaystyle F=\frac{100\ N.m}{4\ m}

F = 25 N

The person needs to apply 25 N to balance the seesaw

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Systems in thermodynamic equilibrium are always in thermal equilibrium, but the converse is not always true. If the connection between the systems allows transfer of energy as heat but does not allow transfer of matter or transfer of energy as work, the two systems may reach thermal equilibrium without reaching thermodynamic equilibrium.

3 0
4 years ago
Derive an expression for the gravitational potential energy U(r) of the object-earth system as a function of the object's distan
Drupady [299]

Answer:

U(r)=-\frac{Gm_Emr^2}{2R^3_E}

Explanation:

We are given that

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r=0,U(0)=0

We know that

Gravitational potential energy=-\int F_gdr

U(r)=-\int\frac{Gm_Emr}{R^3_E}dr

U(r)=-\frac{Gm_Em}{R^3_E}\times \frac{r^2}{2}+C

Substitute r=0 ,U(0)=0

0=0+C

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U(r)=-\frac{Gm_Emr^2}{2R^3_E}

4 0
4 years ago
What is the average speed for the entire graph?
Maru [420]

Answer:

Explanation:

Divide the total distance traveled by the total time spent traveling. This will give you your average speed. . So if Ben traveled 150 miles in 3 hours, 120 miles in 2 hours, and 70 miles in 1 hour, his average speed was about 57 mph.

7 0
3 years ago
An object is thrown upward from the edge of a tall building with a velocity of 10 m/s. Where will the object be 3 s after it is
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We use a fundamental kinematic equation as follows:

V = Vo + g*t. 
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<span>3-Tr-Tf = 3-1-1 = 1 s. Below edge of bldg. </span>

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<span>d = 10*1 + 5*1^2 = 15 m. <---- OPTION C</span>
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The mass of the jupiter is 19*10^26kg &amp;the mass of the earth is 6*10^24kg.if the distance between the jupiter &amp;earth is
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Answer:
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