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3 years ago

Planet that is one astronomical unit from the sun

Physics

1 answer:

777dan777 [17]3 years ago

8 0

Answer:

Earth

Explanation:

"Light travels at a speed of 299,792 kilometers per second; 186,287 miles per second. It takes 499.0 seconds for light to travel from the Sun to the Earth, a distance called 1 Astronomical Unit."

Source : https://image.gsfc.nasa.gov/poetry/venus/q89.html

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A car accelerates in the +x direction from rest with a constant acceleration of a1 = 1.76 m/s2 for t1 = 20 s. At that point the

alex41 [277]

Answer:

(a) $v_1 = a_1t_1 = 1.76 t_1$

(b) It won't hit

Explanation:

(a) the car velocity is the initial velocity (at rest so 0) plus product of acceleration and time t1

$v_1 = v_0 + a_1t_1 = 0 +1.76t_1 = 1.76t_1$

(b) The velocity of the car before the driver begins braking is

$v_1 = 1.76*20 = 35.2m/s$

The driver brakes hard and come to rest for t2 = 5s. This means the deceleration of the driver during braking process is

$a_2 = \frac{\Delta v_2}{\Delta t_2} = \frac{v_2 - v_1}{t_2} = \frac{0 - 35.2}{5} = -7.04 m/s^2$

We can use the following equation of motion to calculate how far the car has travel since braking to stop

$s_2 = v_1t_2 + a_2t_2^2/2$

$s_2 = 35.2*5 - 7.04*5^2/2 = 88 m$

Also the distance from start to where the driver starts braking is

$s_1 = a_1t_1^2/2 = 1.76*20^2/2 = 352$

So the total distance from rest to stop is 352 + 88 = 440 m < 550 m so the car won't hit the limb

8 0

3 years ago

A stuntman with a mass of 82.5 kg swings across a pool of water from a rope that is 12.0 m. At the bottom of the swing the stunt

Brilliant_brown [7]

Answer:

The stuntman will not make it

Explanation:

At the bottom of the swing, the equation of the forces acting on the stuntman is:

$T-mg = m\frac{v^2}{r}$

where:

T is the tension in the rope (upward)

mg is the weight of the man (downward), where

m = 82.5 kg is his mass

$g=9.8 m/s^2$ is the acceleration due to gravity

$m\frac{v^2}{r}$ is the centripetal force, where

v = 8.65 m/s is the speed of the man

r = 12.0 m is the radius of the circule (the length of the rope)

Solving for T, we find the tension in the rope:

$T=mg+m\frac{v^2}{r}=(82.5)(9.8)+(82.5)\frac{8.65^2}{12.0}=1322 N$

Since the rope's breaking strength is 1000 N, the stuntman will not make it.

4 0

3 years ago

How many electrons are available for bonding in oxygen

klasskru [66]

8 electron are needed for bonding

3 0

4 years ago

Which of the following statements is true?

Elenna [48]

I think the answer is c because the rest are false

6 0

4 years ago

Is the series equivalent resistor larger than either resistor, or is it smaller?

VikaD [51]

The equivalent of several resistors in series is always more than the biggest single one, because it's their sum. ... In parallel, the equivalent is always less than the smallest one.

6 0

4 years ago