1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Hatshy [7]
3 years ago
12

A race car makes one lap around a track of radius 50m in 90sec. what is the average velocity?

Physics
1 answer:
drek231 [11]3 years ago
7 0
Average SPEED = 3.491 m/s.

Average VELOCITY = zero.
You might be interested in
An electric vehicle starts from rest and accelerates at a rate of 2.4 m/s2 in a straight line until it reaches a speed of 27 m/s
DENIUS [597]
A) use v=u+at for both

First section, v=27, u=0, a=2.4. You should get 11seconds.
Second section, v=0, u=27, a=-1.3. You should get 21seconds.
This means that the total time is 22seconds.

b) You can either use s=ut+0.5at^2 or v^2=u^2+2as. Personally, I would use the second one as you are not relying on your previous answer.

First section, v=27, u=0, a=2.4. You should get 152m.
Second section, v=0, u=27, a=-1.3. You should get 280m.
This makes your overall displacement 432m.
6 0
3 years ago
Cual es la velocidad de un atleta que se tarda 50 segundos en recorrer una pista de 400 metros
dedylja [7]

Answer:

v = 8 [m/s]

Explanation:

Debemos determinar la velocidad promedio, esta velocidad se define como la relacion entre la distancia recorrida sobre un determinado tiempo.

De esta manera tenemos la siguiente expresion:

v = x/t

donde:

v = velocidad [m/s]

x = distancia = 400 [m]

t = tiempo = 50 [s]

v = 400/50

v = 8 [m/s]

7 0
2 years ago
A phone cord is 4.89 m long. The cord has a mass of 0.212 kg. A transverse wave pulse is produced by plucking one end of the tau
slega [8]

Answer:

Tension in Cord=174 N

Explanation:

Given Data

L (Phone Cord Length)=4.89 m

m (Cord Mass)=0.212 Kg

T (Time for four trips)=0.617 s

Tension=?

Solution

V=λ×f

V=\frac{8*4.89}{0.617}\\ V=63.4m/s

Sigma=\frac{mass}{length}\\ Sigma=\frac{0.212}{4.89}\\ Sigma=0.0433 \frac{kg}{m}

Wave Speed=\sqrt{\frac{Tension}{Sigma} }\\ \\V=\sqrt{\frac{T}{Sigma} }\\ V^{2}=\frac{T}{Sigma}\\  T=V^{2}*Sigma\\ T=(63.4)^{2}*(0.0433)\\ T=174 N

5 0
3 years ago
Dividing up scarce resources refers to resource _____. conservation costs distribution/9919485/7cdfc77f?utm_source=registration
stiks02 [169]
The answer is c. Distrbution
8 0
3 years ago
What is the momentum of a 1.5 * 10 ^ 3 - kil kilogram car as it travels at 30. meters per second due east for 60. seconds ?
serg [7]

Answer:

45000kgm/s due east

Explanation:

Given parameters:

Mass of the car  = 1.5 x 10³kg

Velocity  = 30m/s

Time taken  = 60s

Unknown:

Momentum  = ?

Solution:

Momentum is the quantity of motion a body possess,

     Momentum  = mass x velocity

So;

  Momentum  = 1.5 x 10³ x 30  = 45000kgm/s due east

6 0
3 years ago
Other questions:
  • How far from a -7.80 μC point charge must a 2.40 μC point charge be placed in order for the electric potential energy of the pai
    7·1 answer
  • Which changes in an electric motor will make the motor stronger? Check all that apply.
    8·2 answers
  • Match the following items. 1. empathy a personal view of a situation; ability to understand the senses 2. perception mental heal
    7·1 answer
  • What must the charge (sign and magnitude) of a 1.45-g particle be for it to remain stationary when placed in a downward-directed
    13·1 answer
  • Your boat runs aground at high speed. What should you do FIRST?
    11·1 answer
  • Name the 2 types of tissue that form your skin?
    5·1 answer
  • A 6,200g man runs at a speed of 125m / s. Find the kinetic energy of the running man.
    6·1 answer
  • If a rock is thrown upward on the planet Mars with a velocity of 10 ms, its height in meters seconds later is given by (a) Find
    10·1 answer
  • Which current is produced in homes
    15·2 answers
  • How did black holes get their name
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!