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2 years ago

Which equation correctly represents the gravitational potential energy of a

Physics

2 answers:

Lerok [7]2 years ago

7 0

Answer:

GPE = ME − 1/2 mv^2

Explanation:

Just did it

arsen [322]2 years ago

5 0

Answer:

$PE=ME-\dfrac{1}{2}mv^2$

Explanation:

The mechanical energy of an object is equal to the sum of kinetic energy and the potential energy. Let ME is mechanical energy, KE is kinetic energy then its potential energy PE is given by :

$ME=PE+KE$

Since, KE = (1/2) mv^2

$PE=ME-KE\\\\PE=ME-\dfrac{1}{2}mv^2$

So, $PE=ME-\dfrac{1}{2}mv^2$ correctly represents the gravitational potential energy of a .system

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Kitty [74]

Answer:

68cm

Explanation:

You can solve this problem by using the momentum conservation and energy conservation. By using the conservation of the momentum you get

$p_f=p_i\\mv_1+Mv_2=(m+M)v$

m: mass of the bullet

M: mass of the pendulum

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v2: velocity of the pendulum =0m/s

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this value of v is used as the velocity of the total kinetic energy of the block of pendulum and bullet. This energy equals the potential energy for the maximum height reached by the block:

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g: 9.8/s^2

h: height

By doing h the subject of the equation and replacing you obtain:

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