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sveticcg [70]
3 years ago
11

At one particular moment, a 15.0 kg toboggan is moving over a horizontal surface of snow at 4.40 m/s. After 7.50 s have elapsed,

the toboggan stops. Use a momentum approach to find the magnitude of the average friction force (in N) acting on the toboggan while it was moving.
Physics
1 answer:
MArishka [77]3 years ago
7 0

Answer:

f = 8.8\,N

Explanation:

The moment equation of the toboggan is:

m_{t}\cdot v_{o} - f\cdot \Delta t = 0

The average friction force is:

f=\frac{m_{t}\cdot v_{o}}{\Delta t}

f = \frac{(15.0\,kg)\cdot (4.40\,\frac{m}{s} )}{7.50\,s}

f = 8.8\,N

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