Question

At one particular moment, a 15.0 kg toboggan is moving over a horizontal surface of snow at 4.40 m/s. After 7.50 s have elapsed, the toboggan stops. Use a momentum approach to find the magnitude of the average friction force (in N) acting on the toboggan while it was moving.

Answer 1

Answer:

$f = 8.8\,N$

Explanation:

The moment equation of the toboggan is:

$m_{t}\cdot v_{o} - f\cdot \Delta t = 0$

The average friction force is:

$f=\frac{m_{t}\cdot v_{o}}{\Delta t}$

$f = \frac{(15.0\,kg)\cdot (4.40\,\frac{m}{s} )}{7.50\,s}$

$f = 8.8\,N$