3. Light travels from the Sun to Earth in 8.3 min. Given that the speed of light is 3.00108 m/s, what is the distance in meters
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In a double-slit interference experiment, the distance y of the maximum of order m from the center of the observed interference pattern on the screen is
where D=5.00 m is the distance of the screen from the slits, and
is the distance between the two slits.
The fringes on the screen are 6.5 cm=0.065 m apart from each other, this means that the first maximum (m=1) is located at y=0.065 m from the center of the pattern.
Therefore, from the previous formula we can find the wavelength of the light:
And from the relationship between frequency and wavelength,
, we can find the frequency of the light:
where D=5.00 m is the distance of the screen from the slits, and
The fringes on the screen are 6.5 cm=0.065 m apart from each other, this means that the first maximum (m=1) is located at y=0.065 m from the center of the pattern.
Therefore, from the previous formula we can find the wavelength of the light:
And from the relationship between frequency and wavelength,