With the given values of 
, we have
Try dealing with the powers of 10 first: On the right, we have
Meanwhile, the other values on the right reduce to
Then taking units into account, we end up with the equation
Now we solve for 
:
or, if taking significant digits into account,
F=ma
F= 4x1.2
F= 4.8 N
F= 4gsin30 - Friction
Friction= 19.6 - 4.8 N
Friction= 14.8 N
Friction= u x 4gcos30
14.8 / 4gcos30 = u
u= 0.43596...
u= 0.44
coefficient is 0.44
Answer:
Explanation:
The shear stress due to torque can be calculed by using the following model:
The maximum torque on the section is:
The Torsion Constant for the circular tube is:
![J_{tube} = \frac{\pi}{4}\cdot [(0.053\,m)^{4}-(0.038\,m)^{4}]](https://tex.z-dn.net/?f=J_%7Btube%7D%20%3D%20%5Cfrac%7B%5Cpi%7D%7B4%7D%5Ccdot%20%5B%280.053%5C%2Cm%29%5E%7B4%7D-%280.038%5C%2Cm%29%5E%7B4%7D%5D)
Now, the require output is computed:
Answer:
Explanation:
Unbalanced Force according to newton's second law is the one which causes the object to move or break its state of rest on application of force.
Here the object accelerate to a speed of 4 m/s and moves a distance of 5 m on application of force .
Thus we can say that the applied force is unbalanced in nature.
The range of a projectile can be found directly using:
R = (v²sin2∅) / g
v = √((98 x 9.81)/(sin(90)))
v = 31.0 m/s
