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2 years ago

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If is valid : a ²- b ² = 117 and a - b = 3, then what is the value of the expression a + b ?

1 answer:

juin [17]2 years ago

7 0

Answer:

d is the correct answer from give questions

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The year of Average 11, 15, 17, X+1, 19, X-2, 3 is 14. Find median.

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median of given data is 18

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2 years ago

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At a school, 40% of the sixth-grade students said that hip-hop is their favorite kind of music. If 100 sixth-grade students pref

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2 years ago

At the beginning of April, Owl Corporation has a balance of $12,000 in the Retained Earnings account. During the month of April,

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3 years ago

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slava [35]

I hope this helps you

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3 years ago

A statue is mounted on top of a 21 foot hill. From the base of the hill to where you are standing is 57feet and the statue subte

AleksandrR [38]

Please find the attached diagram for a better understanding of the question.

As we can see from the diagram,

RQ = 21 feet = height of the hill

PQ = 57 feet = Distance between you and the base of the hill

SR= h=height of the statue

$\angle SPR$ =Angle subtended by the statue to where you are standing.

$\angle x=\angle RPQ$ = which is unknown.

Let us begin solving now. The first step is to find the angle $\angle x$ which can be found by using the following trigonometric ratio in $\Delta PQR$ :

$tan(x)=\frac{RQ}{PQ} =\frac{21}{57}$

Which gives $\angle x$ to be:

$\angle x=tan^{-1}(\frac{21}{57})\approx20.22^{0}$

Now, we know that $\angle x$ and $\angle SPR$ can be added to give us the complete angle $\angle SPQ$ in the right triangle $\Delta SPQ$ .

We can again use the tan trigonometric ratio in $\Delta SPQ$ to solve for the height of the statue, h.

This can be done as:

$tan(\angle SPQ)=\frac{SQ}{PQ}$

$tan(7.1^0+20.22^0)=\frac{SR+RQ}{PQ}$

$tan(27.32^0)=\frac{h+21}{57}$

$\therefore h+21=57tan(27.32^0)$

$h\approx8.45 ft$

Thus, the height of the statue is approximately, 8.45 feet.

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2 years ago