In a crash test demonstration, a car with a bowling ball inside hits a brick wall. The bowling ball

Chemistry

1 answer:

mojhsa [17]3 years ago

5 0

Personally I think b is the best answer but if not b then A

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Will a precipitate form when 20.0 ml of 0.10 M Ba(NOxaq) and 50.0 mL of 0.10 M NaCO(aq) are mixed together?

Tom [10]

Answer:

B. Q > K precipitate will form

Explanation:

The reaction is;

Ba(NO3)2(aq) + Na2CO3(aq) ------> BaCO3(s) + 2NaNO3(aq)

Hence the reaction could form a precipitate of BaCO3.

Number of moles of carbonate ions = 50/1000 * 0.10 M = 5 * 10^-3 moles

Number of moles of Barium ions = 20/1000 * 0.10 M = 2 * 10^-3 moles

Total volume after reaction = 20ml + 50ml = 70 ml or 0.07 L

Molarity Barium ions = 5 * 10^-3 moles/ 0.07 L = 0.07 M

Molarity carbonate ions = 2 * 10^-3 moles/ 0.07 L =0.03 M

Q = [Ba^2+] [CO3^2-] = 0.07 * 0.03 = 2.1 * 10^-3

But K = 2.58 × 10 ^− 9

We can clearly see that Q>K therefore precipitate will form

5 0

3 years ago

Balance the following equation:

Firdavs [7]

Answer: a) $2K_2CrO_4+3Na_2SO_3+10HCl\rightarrow 4KCl+3Na_2SO_4+2CrCl_3+5H_2O$

b) 1 mole of $SO_2$ is produced.

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

The skeletal equation is:

$K_2CrO_4+Na_2SO_3+HCl\rightarrow KCl+Na_2SO_4+CrCl_3 +H_2O$