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QveST [7]
3 years ago
9

She wants to travel back to Madison by train. The distance from Chicago to Madison is 147 miles and takes 2.47 hours. If she mak

es no stops, what is her average speed?
Physics
1 answer:
levacccp [35]3 years ago
6 0

Answer:

59.51 mph.

Explanation:

The following data were obtained from the question:

Distance (d) = 147 miles

Time (t) = 2.47 hours.

Speed (S) =?

Speed is defined as the distance travelled per unit time. Mathematically, it is expressed as:

Speed (S) = Distance (d) / time (t)

S = d/t

With the above formula, we can obtain the speed of the girl as illustrated below:

Distance (d) = 147 miles

Time (t) = 2.47 hours.

Speed (S) =?

S = d/t

S = 147 miles / 2.47 hours.

S = 59.51 miles per hour (mph)

Thus, the speed of the girl is 59.51 mph.

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An insulator can do which of the following? Conduct charge through it. Become positively or negatively charged. Transfer protons
ser-zykov [4K]
The correct answer is:
<span>Become positively or negatively charged

In fact, an insulator is a material where charges cannot move freely. Therefore, it can be positively or negatively charge (for example, if it is rubbed against another object, the insulator can remain with an excess of charge), but it cannot transfer charge to other objects.</span>
5 0
3 years ago
The length of the mercury thread is found to be 4cm and 24cm at ice point and steam point respectively on an ungraduated thermom
BabaBlast [244]

Answer:

The difference between ice and steam in Celsius (Centigrade) is 100 deg.

So the difference between and 4 cm and 24 cm of the thread corresponds to 100 deg C.

So 8 cm is 4 cm greater than the ice point

4 cm / 20 cm = 1/5     since the steam point and the ice point are 20 cm apart

Then 1/5 * 100  deg C = 20 deg C   the requested temperature

6 0
3 years ago
A flat horizontal surface with an area of 518 cm^2 is inside a uniform electric field of 1.33 x 10^4 N/C. The angle between the
GarryVolchara [31]

Answer: 576.48 N*m^2/C

Explanation: In order to calculate the electric flux through the any surface we have to take into account the scalar product between the electric field vector and the normal vector to the surface.

So we have:

ФE= E*A= 1.33 * 10^4*0.0518* cos (33.2°)= 576.48 N*m^2/C

3 0
3 years ago
Using the method of dimension, derive an expression for the velocity of sound waves. assume that the velocitu depends on:
Soloha48 [4]

Answer:

v = K √(E / ρ)

Explanation:

Modulus of elasticity has units of N/m², or kg/m/s².

Density has units of kg/m³.

Velocity has units of m/s.

If we divide modulus of elasticity by density, we can eliminate kg:

E / ρ = [kg/m/s²] / [kg/m³]

E / ρ = [m²/s²]

Taking the square root gets us units of velocity:

√(E / ρ) = [m/s]

Multiply by the constant K:

v = K √(E / ρ)

7 0
3 years ago
A tennis ball of mass 44.0 g is held just above a basketball of mass 594 g. With their centers vertically aligned, both are rele
ZanzabumX [31]

Answer:

u = 4.6 m/s

h = 8.01 m

Explanation:

Given:

Mass of the tennis ball, m = 44.0 g

Mass of the basket ball, M = 594 g

Height of fall, h = 1.08m

Now,

we have

u^2-u'^2 = 2as

where, s = distance = h

a = acceleration

u = final speed before the collision

u' = initial speed

since it is free fall case

thus,

a = g = acceleration due to gravity

u' = 0

thus we have

u^2-0^2 = 2\times9.8\tiimes1.08

or

u = \sqrt{21.168}

or

u = 4.6 m/s

b) Now after the bounce, the ball moves with the same velocity

thus, v = v₂

thus,

final speed (v_f) = v = 4.6 m/s

Then conservation of energy says  

\frac{1}{2}mu_1^2+\frac{1}{2}Mu_2^2 = \frac{1}{2}mv_1^2+\frac{1}{2}Mv_2^2  

also

applying the concept of conservation of momentum

we have

mu₁ + Mu₂ = mv₁ + Mv₂

u₁ =velocity of the tennis ball before collision = -4.6 m/s  

u₂ = velocity of the basketball before collision= 4.6 m/s  

v₁ =  velocity of the tennis ball after collision  

v₂ = velocity of the basketball  after collision

substituting the values in the equation, we get

Now,

solving both the equations simultaneously we get

v = (\frac{2M}{m+M})u_1+(\frac{m-M}{m+M})u_2

substituting the values in the above equation we get

v = (\frac{2\times594}{44+594})(-4.6)+(\frac{44-594}{44+594})4.6

or

v = -8.565-3.965

or

v = -12.53m/s

here negative sign depicts the motion of the ball in the upward direction

now the kinetic energy of the tennis ball

K.E = \frac{1}{2}mv^2

or

K.E = \frac{1}{2}44\times 10^{-3}kg\times 12.53^2

or

K.E = 3.45 J

also at the height the K.E will be the potential energy of the tennis ball

thus,

3.45 J = mgh

or

3.45 = 44 × 10⁻³ × 9.8 × h

h = 8.01 m

5 0
3 years ago
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