Answer:
43.68 J
Explanation:
Distance moved= 7.8 m
Force = 5.6 N
Work Done= Distance moved * Force
= 7.8 *5.6
=43.68 Joules
<h2>F = kAρv²</h2>
Explained in the attachment !
<h3>Hope it helps you!!</h3>
efficiency = (useful energy transferred ÷ energy supplied) × 100
It's easy to use this formula, but we have to know both the useful energy and the energy supplied. The drawing doesn't tell us the useful energy, so we have to find a clever way to figure it out. I see two ways to do it:
<u>Way #1:</u>
We all know about the law of conservation of energy. So we know that the total energy coming out must be 250J, because that's how much energy is going in. The wasted energy is 75J, so the rest of the 250J must be the useful energy . . . (250J - 75J) = 175J useful energy.
(useful energy) / (energy supplied) = (175J) / (250J) = <em>70% efficiency</em>
================================
<u>Way #2: </u>
How much of the energy is wasted ? . . . 75J wasted
What percentage of the Input is that 75J ? . . . 75/250 = 30% wasted
30% of the input energy is wasted. That leaves the other <em>70%</em> to be useful energy.
Answer:
See the explanation below,
Explanation:
Momentum is defined as the product of mass by Velocity. In this way, we will replace the following equation in each of the cases.
where:
P = momentum [kg*m/s]
m = mass [kg]
v = velocity [m/s]
A)
B)
![P=100*5\\P=500[kg*m/s]](https://tex.z-dn.net/?f=P%3D100%2A5%5C%5CP%3D500%5Bkg%2Am%2Fs%5D)
C)
![P=1200*15\\P=18000[kg*m/s]](https://tex.z-dn.net/?f=P%3D1200%2A15%5C%5CP%3D18000%5Bkg%2Am%2Fs%5D)
D)
![P=15*1000\\P=15000[kg*m/s]](https://tex.z-dn.net/?f=P%3D15%2A1000%5C%5CP%3D15000%5Bkg%2Am%2Fs%5D)
From higher to lower momentum
C,D,B,A
