Answer:
a= (-g) from the moment the ball is thrown, until it stops in the air.
a = (0) when the ball stops in the air.
a = (g) since the ball starts to fall.
Explanation:
The acceleration is <em>(-g)</em> <em>from the moment the ball is thrown, until it stops in the air</em> because the movement goes in the opposite direction to the force of gravity. In the instant <em>when the ball stops in the air the acceleration is </em><em>(0)</em> because it temporarily stops moving. Then, <em>since the ball starts to fall, the acceleration is </em><em>(g)</em><em> </em>because the movement goes in the same direction of the force of gravity
Answer:
1) We will have excess of electrons
2) The number of electrons transferred equals 
Explanation:
Part a)
Since we know that the charge transfer occurs by the transfer of electrons only as it is given that the carpet has acquired a positive charge it means that it has lost some of the electron's since electrons are negatively charged and if a neutral body looses negative charge it will become positively charged. The electron's that are lost by the carpet will be acquired by the feet of the human thus making us negatively charged.Hence we will gain electrons making us excess in electrons.
Part b)
From charge quantinization principle we have
where
Q = charge of body
n = no of electrons
e = fundamental charge
Applying values in the above equation we get
1. As you push a cereal box across a tabletop, the sliding friction acting on the cereal box_____.
<span> d.) acts in the direction opposite of motion. </span>
2.) Projectile motion is caused by____________.
d.) the downward force of gravity and an initial forward velocity.
The horizontal distance XQ traveled by the bomb is 250 m.
<h3>
Distance X Q</h3>
Let the XQ be the horizontal distance traveled by the bomb.
<h3>Time for the bomb to drop from 100 m</h3>
h = vt + ¹/₂gt
Let the vertical velocity = 0
h = 0 + ¹/₂gt²
h = ¹/₂gt²
2h = gt²
t² = 2h/g
t = √(2h/g)
t = √(2 x 100 / 9.8)
t = 4.5 s
<h3>Horizontal distance traveled by the bomb</h3>
XQ = vx(t)
where;
vx is horizontal speed, = 200 km/hr = 55.56 m/s
XQ = 55.56 x 4.5
XQ = 250 m
Thus, the horizontal distance XQ traveled by the bomb is 250 m.
Learn more about horizontal distance here: brainly.com/question/24784992
#SPJ1
