All categories

4 years ago

Can instantaneous velocity ever be negative?

1 answer:

6 0

it CAN be negative if you consider the velocity as "vector". It CANNOT if you consider the "numerical" velocity..

You might be interested in

A long, straight wire is surrounded by a hollow metal cylinder whose axis coincides with that of the wire. The wire has a charge

miss Akunina [59]

A. - (lambda) per unit length of the inner surface of the cylinderb. (lambda)outer = 3 (lambda)
c. E= 3(lambda)/(4 pi epsilon(0) r^2)

3 0

3 years ago

Read 2 more answers

A car moved 50 km to the North. What is its displacement?

MariettaO [177]

Answer:

50 Km

Explanation:

If the car moved 50 km north and then 50 south its displacement would be 0. if it go in a direction like sw or ne or nw

4 0

3 years ago

A fisherman is fishing from a bridge and is using a "50.0-N test line." In other words, the line will sustain a maximum force of

umka21 [38]

Answer:(a) 50 N

(b)38.34 N

Explanation:

Given

Maximum tension(T) in line 50 N

(a)If line is moving up with constant velocity i.e. there is no acceleration

This will happen when Tension is equal to weight of Fish

T-mg=0

T=mg

Maximum weight in this case will be 50 N

(b)acceleration of magnitude $2.98 m/s^2$

T-mg=ma

$50=m\left ( g+a\right )$

$50=m\left ( 12.78\right )$

m=3.91

Therefore weight is $3.91\times 9.8=38.34 N$

7 0

4 years ago

100 points!!!! Will mark brainliest!!!!!!!!

Scorpion4ik [409]

Answer:

Normal Force, Applied force, Gravitational Force, Spring Force

Explanation:

Normal Force so that he does not fall into trampoline, spring because the trampoline spring down when the force goes down, then up putting force upwards, gravitation because of gravity, and applied because of jumping

8 0

3 years ago

Read 2 more answers

If a m = 74.7 kg m=74.7 kg person were traveling at v = 0.800 c v=0.800c , where c c is the speed of light, what would be the ra

igomit [66]

Answer:

$\frac{E}{E_c} =3.125$

Explanation:

The kinetic energy of a rigid body that travels at a speed v is given by the expression:

$E_c=\frac{1}{2} mv^2$

The equivalence between mass and energy established by the theory of relativity is given by:

$E=mc^2$

This formula states that the equivalent energy $E$ can be calculated as the mass $m$ multiplied by the speed of light $c$ squared.

Where $c$ is approximately $3\times 10^{8} m/s$

Hence:

$E_c=\frac{1}{2} (74.7)*(0.8*3\times 10^{8} )^2=2.15136\times 10^{18} J$

$E=(74.7)*(3\times 10^{8} )^2 =6.723\times 10^{18} J$

Therefore, the ratio of the person's relativistic kinetic energy to the person's classical kinetic energy is:

$\frac{E}{E_c} =\frac{6.723\times 10^{18}}{2.15136\times 10^{18}} =3.125$

4 0

3 years ago