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sdas [7]
4 years ago
7

Can instantaneous velocity ever be negative?

Physics
1 answer:
Nana76 [90]4 years ago
6 0
<span> it CAN be negative if you consider the velocity as "vector". It CANNOT if you consider the "numerical" velocity..</span>
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A long, straight wire is surrounded by a hollow metal cylinder whose axis coincides with that of the wire. The wire has a charge
miss Akunina [59]
A. - (lambda) per unit length of the inner surface of the cylinder<span>b. (lambda)outer = 3 (lambda)
</span><span>c. E= 3(lambda)/(4 pi epsilon(0) r^2)</span>

3 0
3 years ago
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A car moved 50 km to the North. What is its displacement?
MariettaO [177]

Answer:

50 Km

Explanation:

If the car moved 50 km north and then 50 south its displacement would be 0. if it go in a direction like sw or ne or nw

4 0
3 years ago
A fisherman is fishing from a bridge and is using a "50.0-N test line." In other words, the line will sustain a maximum force of
umka21 [38]

Answer:(a) 50 N

(b)38.34 N

Explanation:

Given

Maximum tension(T) in line 50 N

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This will happen when Tension is equal to weight of Fish

T-mg=0

T=mg

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50=m\left ( g+a\right )

50=m\left ( 12.78\right )

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7 0
4 years ago
100 points!!!! Will mark brainliest!!!!!!!!
Scorpion4ik [409]

Answer:

Normal Force, Applied force, Gravitational Force, Spring Force

Explanation:

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8 0
3 years ago
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If a m = 74.7 kg m=74.7 kg person were traveling at v = 0.800 c v=0.800c , where c c is the speed of light, what would be the ra
igomit [66]

Answer:

\frac{E}{E_c} =3.125

Explanation:

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E=mc^2

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Where c is approximately 3\times 10^{8} m/s

Hence:

E_c=\frac{1}{2} (74.7)*(0.8*3\times 10^{8} )^2=2.15136\times 10^{18} J

E=(74.7)*(3\times 10^{8} )^2 =6.723\times 10^{18} J

Therefore,  the ratio of the person's relativistic kinetic energy to the person's classical kinetic energy is:

\frac{E}{E_c} =\frac{6.723\times 10^{18}}{2.15136\times 10^{18}} =3.125

4 0
3 years ago
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