Answer:
Moles of NO₂ = 0.158
Explanation:
SO 2 ( g ) + NO 2 ( g ) ⇄ SO 3 ( g ) + NO ( g )
According to the law of mass equation
=
⇒ 3.10 = At equilibrium [SO₃] = [NO]
⇒ [NO₂] =
⇒ [NO₂] = 0.158
So. number of moles of NO₂ at equilibrium added = 0.158
Answer:
0.142 M
Explanation:
Let's consider the neutralization reaction between calcium hydroxide and hydrochloric acid.
Ca(OH)₂ + 2 HCl → CaCl₂ + 2 H₂O
25.8 mL of 0.183 M HCl are used. The reacting moles are:
0.0258 L × 0.183 mol/L = 4.72 × 10⁻³ mol
The molar ratio of Ca(OH)₂ to HCl is 1:2. The reacting moles of Ca(OH)₂ are 1/2 × 4.72 × 10⁻³ mol = 2.36 × 10⁻³ mol
2.36 × 10⁻³ moles of Ca(OH)₂ are contained in 16.6 mL. The molarity of Ca(OH)₂ is:
M = 2.36 × 10⁻³ mol/0.0166 L = 0.142 M
Well, Tin(Sn) is in Period 5 and a member of group 14.
Metabolism is when you don’t gain weight after eating a lot.