Question

Select the correct answer.

Answer 1

Answer:

85

Explanation:

Answer 2

Answer:

% composition of glucose =  85 %

Explanation:

Given Data

moles of glucose (C₆H₁₂O₆) = 1.3 mole

Total mass of mixture = 276 g

percent composition of glucose (C₆H₁₂O₆) = ?

Solution

Number of moles are given so we find out the mass of C₆H₁₂O₆

mass = moles × molar mass

Molar mass of glucose = 180.156 g/mol

mass = 1.3 mol × 180.156 g/mol

mass = 234.2 g

Now we find out the percent composition of glucose

% composition =  (mass of compound ÷ mass of mixture) × 100

% composition =  ( 234.2 g ÷ 276 g) × 100

% composition =  0.85 × 100

% composition =  85 %