Hello,
Answer A: no solution
line 1: (-6,3), (3,6)==>y-3=(x+6)*3/9==>x-3y=-15 (1)
line 2: (-3,1), (3,3)==>y-1=(x+3)2/6==> x-3y=-6 (2)
(1)-(2)==>0x=-9 ==> no solution
line 1 // line 2
Answer:
answer is A
Step-by-step explanation:
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Answer:
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Step-by-step explanation:
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You have to move the decimal
Answer:
The other zeros are -2 and 3.
Step-by-step explanation:
As 1 is a zero then (x - 1) is a factor so we divide:
x - 1 )x^3-2x^2-5x+6(x^2-x-6
x^3-x^2
-x^2-5x
-x^2+x
-6x+6
-6x+6
...........
x^2 - x - 6 = 0
(x - 3)(x + 2)
x = -2, 3.