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andreev551 [17]
3 years ago
6

For an aqueous solution of sodium chloride (NaCl) .Determine the molarity of 3.45L of a solution that contains 145g of sodium

Chemistry
1 answer:
worty [1.4K]3 years ago
6 0
Molar mass NaCl = 58.44 g/mol

number of moles:

mass NaCl / molar mass

145 / 58.44 => 2.4811 moles of NaCl

Volume = 3.45 L

Therefore :

M = moles / volume in liters:

M = 2.4811 / 3.45

M = 0.719 mol/L⁻¹

hope this helps!
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0.0432M

Explanation:

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Data obtained from the question include:

Vb (volume of the base) = 54mL

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Using CaVa/CbVb = nA/nB, the concentration of the acid can easily be obtained as shown below:

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