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Ann [662]
3 years ago
14

Help me slove this problem 115 divided by 2

Physics
2 answers:
zhenek [66]3 years ago
4 0
115 divided by 2 equals 57.5
Umnica [9.8K]3 years ago
4 0
115 divided by 2 equals 57.5.
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A rock thrown with a horizontal velocity of 20m/s from a cliff that is 125m above level ground. If air resistance is negligible,
Alexxandr [17]

Answer: c

Explanation: 125/20 =6.25

6 0
3 years ago
A roller skater of 47kg moving with a velocity of 12 m/s to the east picks up a bag of 6.0 kg. What is the final velocity of the
WITCHER [35]

Answer:

v_f = 10.85 m/s

Explanation:

We will apply the law of conservation of momentum here:

m_{1}v_{1i} + m_{2}v_{2i} = m_{1}v_{1f}+m_{2}v_{2f}\\

where,

m₁ = mass of roller skater = 47 kg

m₂ = mass of bag = 6 kg

v_1i = initial speed of roller skater = 12 m/s

v_2i = initial speed of the bag = 0 m/s

v_1f = final speed of the roller skater = ?

v_2f = final speed of the bag = ?

Both the bag and the skater will have same speed at the end because kater is carrying the bag:

v_1f = v_2f = v_f

Therefore, the equation will become:

(47\ kg)(12\ m/s)+(6\ kg)(0\ m/s)=(47\ kg)(v_{f})+(5\ kg)(v_{f})\\564\ N.s = (47\ kg+5\ kg)(v_{f})\\v_{f} = \frac{564\ N.s}{52\ kg}\\

<u>v_f = 10.85 m/s</u>

8 0
3 years ago
What is the ratio of the gravitational pull of the sun on the moon to that of the earth on the moon? (assume the distance of the
professor190 [17]

Acceleration of Gravity Sun-Moon System

G = 6.67260E-11 m^3/(kg sec^2)
m1 = mass of Sun = 1.989E+30 kg
m2 = mass of Moon = 7.3476E+22 kg
r = distance between Sun and Moon = distance between Sun and Earth - distance between Earth and Moon = 149,600,000 km - 384,400 km

<span>g = 0.00596 m/s^2</span>
5 0
3 years ago
Deep-focus earthquakes form at subduction zones as well as continental-continental plate boundaries True Or False
kipiarov [429]

Answer:

The answer is true, they can form at both.

6 0
3 years ago
Read 2 more answers
I need to solve this problem ​
castortr0y [4]

Answer:

λ = V / f      the wavelength versus the frequency

V = f λ      and V (speed) proportional λ    for a fixed frequency

F = f^2 * (M / L) * λ^2 = (f * λ)^2 * (M / L)^2    force (tension) on string at a given frequency

F2 / F1 = (λ2 / λ1)^2    other items are constant

Let λ1  = 6   then λ2 must be 3/2 λ1   for a constant length

F2 / F1 = (6 / 4)^2 = 9/4

The tension must be increased to 9 / 4 of  the original tension

Check: if the frequency is fixed then V will be larger for a larger wavelength  (situation 2)

One can also write V = (F / (M / L))^1/2

Then for fixed M  L    

F2 / F1 = (V2 / V1)^2

Since V = f λ      Velocity is proportional to λ  for a fixed frequency

Then if V2 / V1 = 3 / 2     F2 = 9/4 F1

 

4 0
2 years ago
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