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Gre4nikov [31]
2 years ago
9

I need the answers fast !!! this test is due today at 11:59

Mathematics
1 answer:
zhenek [66]2 years ago
5 0

Answer:

Options 2 and 6

Step-by-step explanation:

Those are the locations of the points on the graph. If you look closely, you will see that it counts by twos.

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Your basketball team scored 4 fewer than twice as many points, x, as the other team. a. Write an expression for the number of po
velikii [3]

Answer:

A) p = 2x - 4  for the expression. B) Your team scored 44 points.

Step-by-step explanation:

Let <u>P</u> represent the points your team made.

Since the question says "Your basketball team scored 4 fewer than twice as many points as the other team." this is how I came up with the expression.

p = 2x - 4 ( our points = 2 times more then the other teams points minus 4.

Using this expression and the given information that the other team made 24 points, I solved B.

44 = 2(24) - 4.

3 0
3 years ago
Please help meeeeeeeeeeeeeee
stepladder [879]

Answer:

multiply it by 2

Step-by-step explanation:

3 0
2 years ago
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There is a 60% chance that your flight will leave on time
OLEGan [10]
A 40% chance





Unless!
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It’s a trick question?
6 0
3 years ago
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A four year old is going to spin around with his arms stretched out 100 times. From past experience, his father knows it takes a
Sati [7]

Answer:

P(X \geq0.55) \leq 0.22

Step-by-step explanation:

Using central Limit Theorem (CLT), The sum of 100 random variables;

Y=X_1+X_2+...+X_{100} is approximately normally distributed with

Y ~ N (100 × \frac{1}{3^2} ) = N ( 50, \frac{100}{9} )

The approximate probability that it will take this child over 55 seconds to complete spinning can be determined as follows;

N ( 50, \frac{100}{9} )

P(Y>55) =P(Z>\frac{55-50}{10/3})

P(Y>55) =P(Z>1.5)

P(Y>55) =\phi (-1.5)

P(Y>55) =0.0668

Using Chebyshev's inequality:

P(|X-\mu\geq K)\leq \frac{\sigma^2}{K^2}

Let assume that X has a symmetric distribution:

Then:

2P(X-\mu\geq K)\leq) \frac{\sigma^2}{K^2}

2P(X \geq \mu+K)\leq) \frac{\sigma^2}{K^2}

2P(X\geq0.5+0.05)\leq \frac{\frac{1}{\frac{3^2}{100} } }{0.05^2}               where: (\sigma^2 = \frac{1}{3^2/100})

P(X \geq0.55) \leq 0.22

6 0
3 years ago
On Monday, three hundred forty students went on a trip to the zoo. All eight buses were filled and four
VMariaS [17]

Answer:

42.5

Step-by-step explanation:

divide it by 8.

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3 years ago
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