X²+y² =(Radius)²
x²+y² =10². So the radius is 10
If is
x > 2 or x < 7 ⇒ x is any real number
If is
x > 2 and x < 7 ⇒ 2 < x < 7
A set of all numbers that are greater than 2 and less than 7.
Look at the picture.
Answer:
10000
Step-by-step explanation:
Well substitute it
(5*2)^4
now follow order of operations (Parenthesis, exponents, multipication-division left to right, etc.)
5*2=10
10^4=10000
so the answer would be
10000 if y is 2
Answer:
x = 2, y = 6
(2, 6)
Step-by-step explanation:
The system of equations is solved when we find the "x" and "y" pair that is true for both equations.
We can use elimination, which is when we eliminate one of the variables. This can be done when both equations have a variable that has the same number.
Make both equations have "12y". Multiply each term by the same number.
-7x + 4y =10 }x3 => -21x + 12y = 30
-5x + 3y = 8 }x4 => -20x + 12y = 32
Subtract the equations from each other to get rid of 12y.
. -20x + 12y = 32
<u>- -21x + 12y = 30</u>
. 1x + 0y = 2 0y is nothing and 1x is x.
. x = 2 We have solved for x.
Now solve for y.
Use one of the equations:
-5x + 3y = 8 Substitute x for 2
-5(2) + 3y = 8 Simplify
-10 + 3y = 8 Start isolating x. Add 10 to both sides
3y = 18 Divide both sides by 3
y = 6 Solved for y.
The system of equations intersect at (2, 6).
