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oksano4ka [1.4K]
3 years ago
7

Classify each polygon by its number of sides.

Mathematics
2 answers:
zhuklara [117]3 years ago
7 0
Shape three is a decagon

shape two is a dodecagon

shape one is a "hexagon" has 6 sides
djyliett [7]3 years ago
4 0

Answer:  

A 2-dimension closed figures with a number of sides is called Polygon.

If it has 7 sides it is called Heptagon,

If it has 12 sides it is called Dodecagon,

If it has 6 sides it is called Hexagon,

If it has 10 sides it is called Decagon,

If it has 8 sides it is called octagon,

If it has 5 sides it is called Pentagon,

Since, First figure has 6 sides therefore, it is a hexagon,

While, Second figure has 12 sides therefore, why it is a Dodecagon,

And, Third figure has 10 sides therefore, it is a Decagon.

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25/100 X 120 = 30

total streaming cost $30

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Geometry word problem:
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listen look and listen end learn

Step-by-step explanation:

<em>listen </em><em>and </em><em>learn </em><em>hahaha</em>

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2 years ago
roman mixes 1.5 liters of orange juice w 800 milliliters of pineapple juice to make punch, for every 1 liter there are 1000 mill
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2.3 liters

Step-by-step explanation:

800 ml (milliliters) = 0.8 l (liters)

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3 years ago
Suppose that each child born is equally likely to be a boy or a girl. Consider a family with exactly three children. Let BBG ind
Gemiola [76]

Answer:

(a)

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

(b)

i.

1\ girl = \{GBB, BBG, BGB\}

P(1\ girl) = 0.375

ii.

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

P(Atleast\ 2 \ girls) = 0.5

iii.

No\ girl = \{BBB\}

P(No\ girl) = 0.125

Step-by-step explanation:

Given

Children = 3

B = Boys

G = Girls

Solving (a): List all possible elements using set-roster notation.

The possible elements are:

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

And the number of elements are:

n(S) = 8

Solving (bi) Exactly 1 girl

From the list of possible elements, we have:

1\ girl = \{GBB, BBG, BGB\}

And the number of the list is;

n(1\ girl) = 3

The probability is calculated as;

P(1\ girl) = \frac{n(1\ girl)}{n(S)}

P(1\ girl) = \frac{3}{8}

P(1\ girl) = 0.375

Solving (bi) At least 2 are girls

From the list of possible elements, we have:

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

And the number of the list is;

n(Atleast\ 2 \ girls) = 4

The probability is calculated as;

P(Atleast\ 2 \ girls) = \frac{n(Atleast\ 2 \ girls)}{n(S)}

P(Atleast\ 2 \ girls) = \frac{4}{8}

P(Atleast\ 2 \ girls) = 0.5

Solving (biii) No girl

From the list of possible elements, we have:

No\ girl = \{BBB\}

And the number of the list is;

n(No\ girl) = 1

The probability is calculated as;

P(No\ girl) = \frac{n(No\ girl)}{n(S)}

P(No\ girl) = \frac{1}{8}

P(No\ girl) = 0.125

7 0
3 years ago
Sadie measured the floor of her storage unit, which is rectangular. It is 9 meters wide and 10 meters from one corner to the opp
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Answer:

lack

Step-by-step explanation:

4 0
3 years ago
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