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klio [65]
3 years ago
11

Jeremy spent $26.50 for 5.5lb. What would be the price of 1 pound of dog food

Mathematics
1 answer:
NikAS [45]3 years ago
4 0

Answer:

$4.81

Step-by-step explanation:

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2 years ago
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Tom jogged 3/5 on Monday and 2/6 mile on Tuesday. How much farther did Tom jog on Monday than on Tuesday
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You will want to subtract the amount he ran on Monday from the amount on Tuesday. In order to subtract fractions, we must set them to the same denominator (bottom number). In order to do this, we must multiply 3/5 by 6/6 (the denominator on tuesday) which gets us 18/30. Then, for Tuesday, we must multiply 2/6 by 5/5 (the denominator on Monday) which is 10/30. Now, we can do Monday-Tuesday, 18/30-10/30 which gets us 8/30, if we simplify this, we get 4/15 :)
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2 years ago
Convert 3x-4y = 9 to slope intercept form. What are the slope and y - intercept ?
Alecsey [184]

Answer:

Slope intercept form; -4y = -3x + 9

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2 years ago
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ennifer buys a new typewriter for $590. Jennifer puts 20% down and will pay $70 a month for the next 10 months. What's the total
VMariaS [17]
The total amount paid in monthly payments is found by multiplying $70 by 10.  This is the only information that is needed to find the amount paid over 10 months.

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8 0
3 years ago
Insurance companies are interested in knowing the population percent of drivers who always buckle up before riding in a car. The
Tems11 [23]

Answer:

The 84% confidence interval for the population proportion that claim to always buckle up is (0.74, 0.80).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

They randomly survey 387 drivers and find that 298 claim to always buckle up.

This means that n = 387, \pi = \frac{298}{387} = 0.77

84% confidence level

So \alpha = 0.16, z is the value of Z that has a p-value of 1 - \frac{0.16}{2} = 0.92, so Z = 1.405.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.77 - 1.405\sqrt{\frac{0.77*0.23}{387}} = 0.74

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.77 + 1.405\sqrt{\frac{0.77*0.23}{387}} = 0.8

The 84% confidence interval for the population proportion that claim to always buckle up is (0.74, 0.80).

6 0
3 years ago
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