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ale4655 [162]
3 years ago
15

How many minutes are each half in soccer ?

Physics
1 answer:
Komok [63]3 years ago
3 0
15 minutes each half
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PHYSICS 50 POINTS PLEASE HELP
tangare [24]

Answer:

One way to look at Newton’s three laws of motion is this:

The third law states what forces are. That is, all forces are interactions between two different objects. If one object is interacting with another, then equal and opposite forces act on each object. So no force acts alone. When you exert a force on something, it is exerting the identical force back on you.

The first and second laws deal with the consequences of the forces that act on an object. The first law says that in the absence of a net force on an object, it simply continues doing whatever it was already doing. If it is at rest, it will remain at rest. If it is in motion, it will continue with that same motion - at constant speed and in the direction it was already traveling.

The second law says what happens if there is a net force on the object. In that case, the object accelerates - either by changing its speed, its direction, or both - in proportion and in the direction of the net force that acts on it. The amount of acceleration depends the object’s mass. That is, the larger the mass the smaller the acceleration for a given net force. The first and second laws can be summarized in the mathematical expression

F = ma

where F is the vector sum of all the forces that act on the object at any given moment (i.e., the net force), m is the mass of the object, and a is the acceleration of the object due to the net force at that moment - and is always in the same direction of the net force.

And notice that in a way, the first law is then “contained” within the second. That is, if the net force is zero on an object, then so is the acceleration. That is, either the object is (still) at rest or, if already in motion, the velocity didn’t change, in either case, the acceleration was zero.

Explanation:

4 0
3 years ago
Read 2 more answers
How much tension must a rope withstand if it is used to accelerate a 1700-kg car
olya-2409 [2.1K]
I don’t know it i just need points
7 0
4 years ago
The displacement ‘x’of a particle is dependent on time ‘t’according to the relation X= 3 -5t +<img src="https://tex.z-dn.net/?f=
rusak2 [61]

Answer:

Explanation:

A.

8 0
3 years ago
How much work is required to lift 40 N 1.5 M
LiRa [457]

Answer: 200 joules I think.

Explanation:

3 0
3 years ago
A baseball of mass m1 = 0.45 kg is thrown at a concrete block m2 = 7.25 kg. The block has a coefficient of static friction of μs
miskamm [114]

Answer:

a. v = \frac{mu_sm_2g\Delta t}{m_1}

b. 21.64 m/s

Explanation:

Let g = 9.81m/s2

a. The weight of the block is product of its mass and gravitational acceleration

W = m_2g = 7.25*9.81 = 71.1225N

which is also the normal force acting on the block from the floor so it stays balanced.

N = 71.225N

The static friction of the block is product of its normal force from the floor and the friction coefficient

F_s = \mu_sN = \mu_sW = mu_sm_2g

For the block to move, the force generated by the impact must be at least equal to the static friction.

F = F_s = mu_sm_2g

The impulse is product of this force and time duration of impact.

I = F\Delta t = mu_sm_2g\Delta t

As impulse is generated by change in momentum of the ball, which is product of its mass and velocity v

I = \Delta p = m_1\Delta v

mu_sm_2g\Delta t = m_1 v

v = \frac{mu_sm_2g\Delta t}{m_1}

b. v = \frac{mu_sm_2g\Delta t}{m_1} = \frac{0.74*7.25*9.81*0.185}{0.45} = 21.64 m/s

8 0
3 years ago
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