Answer:
Solids - Bricks , wood , Pottery, Bucket
Liquid - Water, soap, Sanitizers.
Gases - Aerosol in Deodorants, Chlorofluorocarbons in Fire extinguishers , Butane in lighters.
 
        
             
        
        
        
Answer:
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Explanation:
hiiii look forward but I don't know how to do it
 
        
             
        
        
        
A physical change in something doesn't change what the it is. For example, if you break glass, it will still be glass. In a chemical change where there is a chemical reaction, a new thing is formed and energy is either given off or absorbed. For example, when you burn a log. The carbon in the log is reacting to the oxygen to create ashe and smoke
        
                    
             
        
        
        
Answer:
no: 
Explanation:
it would grow and no longer be able to fit through the loop due to the hot air expanding.
 
        
             
        
        
        
Answer:
a. 2v₀/a   b. 2v₀/a  
Explanation:
a. Since you are moving with a constant velocity v₀, the distance, s you cover in time = t max is s = v₀t.
Since the dragster starts from rest with an acceleration, a, using
s' = ut + 1/2at² where u = 0 and s' = distance moved by dragster
s' = 0t + 1/2at²
s' = 1/2at²
Since the distance moved by me and the dragster must be the same, 
s = s'
v₀t. =  1/2at²
v₀t. - 1/2at² = 0
t(v₀ - 1/2at) = 0
t= 0 or v₀ - 1/2at = 0
t= 0 or v₀ = 1/2at 
t= 0 or t = 2v₀/a  
So the maximum time tmax = 2v₀/a
b. Since the distance covered by me to meet the dragster is s = v₀t in time, t = tmax which is also my distance from the dragster when it started. So, my distance from the dragster when it started is s =  v₀(2v₀/a) 
= 2v₀/a