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siniylev [52]
3 years ago
10

Please don’t troll. I need help on this

Mathematics
2 answers:
soldier1979 [14.2K]3 years ago
6 0

Answer:

Sally is currently 4 years old.

Step-by-step explanation:

<em>Kaden is 18 years older than Sally now. In 5 years, Kaden will be 3 times as old as Sally. How old is Sally now?</em>

<em />

Let Kaden's current age be k and Sally's current age be s. We can write the following algebraic equation using the fact that Kaden is currently 18 years older than Sally:

k=s+18

Next, we will use the fact that in 5 years, Kaden will be 3 times as old as Sally. If Kaden and Sally's current ages are k and s respectively, then their ages in 5 years will be k+5 and s+5 respectively. Therefore, we have:

k+5=3(s+5)

We have two equations with two variables. To solve for either variable, we need to create an equation with only one variable. Therefore, let's substitute the first equation into the second:

(s+18)+5=3(s+5)

Distribute and combine like terms:

s+18+5=3s+15,\\s+23=3s+15

Subtract s from both sides, then subtract 15 from both sides:

8=2s

Divide both sides by 2:

s=\frac{8}{2}=\boxed{4}

Therefore, Sally is currently 4 years old.

aleksklad [387]3 years ago
6 0

Answer:

Sally is 4 years old now.

Step-by-step explanation:

Let Sally's age = x

Kaden's age = x + 18

In 5 years, they are both 5 years older than now.

Sally will be x + 5

Kaden will be x + 18 + 5 = x + 23

"<em>In 5 years, Kaden will be 3 times as old as Sally.</em>"

x + 23 = 3(x + 5)

x + 23 = 3x + 15

-2x = -8

x = 4

Answer: Sally is 4 years old now.

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NEED HELP NOW I have 31 stamps total. I have 4 more 1-cent stamps than 8-cent stamps and twice as many one cent stamps as 12 cen
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-------------

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