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3 years ago

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What chemicals must be cycled through a Martian environment in order for the planet to be habitable for life? Describe how scien

tists intend to make those resources available in such a harsh environment.

1 answer:

photoshop1234 [79]3 years ago

4 0

The scientists intend to make chemicals

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Explain how boiling and evaporating are alike and how they are differant

julsineya [31]

Answer:

The main difference between evaporation and boiling are : 1. Evaporation takes place at all temperatures, while boiling occurs at a particular temperature. 2. Evaporation takes place from the surface, whereas the entire liquid boils. 3. Evaporation can occur using the internal energy of the system, while boiling requires an external source of heat.

7 0

3 years ago

Non-examples of air pressure

Anuta_ua [19.1K]

No pressure

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8 0

3 years ago

Consider the following reaction at equilibrium: 2NH3 (g) N2 (g) + 3H2 (g) Le Châtelier's principle predicts that the moles of H2

Lilit [14]

Answer:

A decrease in the total volume of the reaction vessel (T constant)

Explanation:

Le Châtelier's principle predicts that the moles of H2 in the reaction container will increase with a decrease in the total volume of the reaction vessel.
<em><u>According to the Le Chatelier's principle, when a chnage is a applied to a system at equilibrium, then the equilibrium will shift in a way that counteracts the effect causing it.</u></em>
In this case, a decrease in volume means there is an increase in pressure, therefore the equilibrium will shift towards the side with the fewer number of moles of gas.

3 0

3 years ago

The standard cell potential Ec for the reduction of silver ions with elemental copper is 0.46V at 25 degrees celsius. calculate

Cloud [144]

Answer : The $\Delta G$ for this reaction is, -88780 J/mole.

Solution :

The balanced cell reaction will be,

$Cu(s)+2Ag^+(aq)\rightarrow Cu^{2+}(aq)+2Ag(s)$

Here, magnesium (Cu) undergoes oxidation by loss of electrons, thus act as anode. silver (Ag) undergoes reduction by gain of electrons and thus act as cathode.

The half oxidation-reduction reaction will be :

Oxidation : $Cu\rightarrow Cu^{2+}+2e^-$

Reduction : $2Ag^++2e^-\rightarrow 2Ag$

Now we have to calculate the Gibbs free energy.

Formula used :

$\Delta G^o=-nFE^o$

where,

$\Delta G^o$ = Gibbs free energy = ?

n = number of electrons to balance the reaction = 2

F = Faraday constant = 96500 C/mole

$E^o$ = standard e.m.f of cell = 0.46 V

Now put all the given values in this formula, we get the Gibbs free energy.

$\Delta G^o=-(2\times 96500\times 0.46)=-88780J/mole$

Therefore, the $\Delta G$ for this reaction is, -88780 J/mole.

7 0

3 years ago

An electron in a hydrogen atom has orbital quantum number l = 7. how many possible values of the magnetic quantum number ml coul

MA_775_DIABLO [31]

A total of 15 magnetic quantum values are possible.

<h3>What is a Magnetic quantum number?</h3>

One of the four quantum numbers that describe an electron's position in relation to the nucleus is its magnetic quantum number.

Between spin and azimuthal quantum numbers, the magnetic quantum number comes in third on the list. The electron is positioned in one of the various orbitals formed by the division of the subshells (such as s, p, d, and f). It specifies the spatial direction of an orbital of certain energy (n) and form (I). The number of orbitals in each subshell is given as 2+1, where is the azimuthal quantum number. We can determine the orbital in each sub-shell using that method.

We are aware that there are between -l and +l conceivable magnetic quantum numbers.

Here l = 7

Thus, the range of magnetic quantum numbers will be -7 to +7.

Thus, the magnetic quantum numbers are as follows:

-7, -6, -5, -4,-3,-2,-1, 0, 1,2,3,4, 5, 6,7

This opens up a total of 15 magnetic quantum numbers.

To learn more about Magnetic Quantum, visit:

brainly.com/question/24204727

#SPJ4

6 0

2 years ago