Answer:
The maximum electric field ![E_{max}= 0.132V/m](https://tex.z-dn.net/?f=E_%7Bmax%7D%3D%200.132V%2Fm)
Explanation:
From the question we are told that
The diameter is ![d = 3.3 cm = \frac{3.3}{100} = 0.033m](https://tex.z-dn.net/?f=d%20%3D%203.3%20cm%20%3D%20%5Cfrac%7B3.3%7D%7B100%7D%20%3D%200.033m)
The magnetic field of the cylinder is
The frequency is ![f = 15Hz](https://tex.z-dn.net/?f=f%20%3D%2015Hz)
The radial distance is ![d_r = 1.4cm = \frac{1.4}{100} = 0.014m](https://tex.z-dn.net/?f=d_r%20%3D%201.4cm%20%3D%20%5Cfrac%7B1.4%7D%7B100%7D%20%20%3D%200.014m)
This magnetic field can be represented mathematically as
![B(t) = B_i + B_1sin (wt + \o_i)](https://tex.z-dn.net/?f=B%28t%29%20%3D%20B_i%20%2B%20B_1sin%20%28wt%20%2B%20%5Co_i%29)
The initial magnetic field is the average between the variation of the magnetic field which is represented as
![B_i = \frac{30 + 29.6}{2}](https://tex.z-dn.net/?f=B_i%20%3D%20%5Cfrac%7B30%20%2B%2029.6%7D%7B2%7D)
![= 29.8T](https://tex.z-dn.net/?f=%3D%20%2029.8T)
Then
is the amplitude of the resultant field is mathematically evaluated as
![B_1 = \frac{30.0 - 29.6}{2}](https://tex.z-dn.net/?f=B_1%20%3D%20%5Cfrac%7B30.0%20-%2029.6%7D%7B2%7D)
![= 0.200T](https://tex.z-dn.net/?f=%3D%200.200T)
The electric field induced can be represented mathematically as
![E = \frac{1}{2} [\frac{dB }{dt} ]d_r](https://tex.z-dn.net/?f=E%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%20%5B%5Cfrac%7BdB%20%7D%7Bdt%7D%20%20%5Dd_r)
![= \frac{d_r}{2} \frac{d}{dt} (B_i + B_1 sin (wt + \o_o))](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7Bd_r%7D%7B2%7D%20%5Cfrac%7Bd%7D%7Bdt%7D%20%28B_i%20%2B%20B_1%20sin%20%28wt%20%2B%20%5Co_o%29%29)
![= \frac{1}{2} (B wr cos (wt + \o_o))](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B1%7D%7B2%7D%20%28B%20wr%20cos%20%28wt%20%2B%20%5Co_o%29%29)
At maximum electric field ![cos (wt + \o_o) = 1](https://tex.z-dn.net/?f=cos%20%28wt%20%2B%20%5Co_o%29%20%20%3D%201)
![E_{max} = \frac{1}{2} B_1 wd_r](https://tex.z-dn.net/?f=E_%7Bmax%7D%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20B_1%20wd_r)
![E_{max} = \frac{1}{2} B_1 2 \pi f d_r](https://tex.z-dn.net/?f=E_%7Bmax%7D%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20B_1%202%20%5Cpi%20f%20d_r)
![= \frac{1}{2} (0.200) (2 \pi (15 ))(0.014)](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B1%7D%7B2%7D%20%280.200%29%20%282%20%5Cpi%20%2815%20%29%29%280.014%29)
![E_{max}= 0.132V/m](https://tex.z-dn.net/?f=E_%7Bmax%7D%3D%200.132V%2Fm)
The answer to this question would be: 1m/s
When you are walking to the north with 2m/s velocity, the stationary object(velocity=0m/s) will look like moving south at 2m/s velocity. That happens because the relative distance between you and the object is reduced by 2m/s in both conditions. In this question, the man seems like have 3m/s velocity. The real velocity should be:
3m/s - 2m/s = 1m/s
Answer:
Explanation:
The centripetal acceleration is expressed as;
a = v²/r
a is the acceleration = 50m/s²
v is the velocity = 10m/s
r is the radius
To get the radius
r = v²/a
r = 10²/50
r = 100/50
r = 2m
Hence its radius is 2m
An advantage to having a computer is it has fast and easy access to many resources, research articles, news sources, reading material, and activities. A disadvantage is being on the computer too much isn’t good people will spend their whole day playing videos games instead of learning.
The correct answer is A, 2x^3 - x^2 +3x +7