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EleoNora [17]
4 years ago
7

Describe in detail how you might experimentally determine the density of a cylindrical shaped object. Explain all steps clearly

Physics
1 answer:
pashok25 [27]4 years ago
4 0
Tbh idk I need help to
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What are the set of equations called that can be used to quantify motion in the case of uniform acceleration?
KATRIN_1 [288]
The kinematic equations are used to <span>quantify motion in the case of uniform acceleration.

The other name is : SUVAT equations, where the letters signify: 
 displacement (s),
initial velocity (u),
 final velocity (v),
acceleration (a), and
 time (t).

There are three equations are attached in the picture: </span>

7 0
4 years ago
a rocket has a mass 250(10^3) slugs on earth. Specify its mass in si units and its weight in si unites. if the rocket is on the
Katena32 [7]

Answer:

W_{earth} = 35.74 * 10^6 N : Rocket weight on earth

W_{moon} = 5.91 * 10^6 N : Rocket weight on moon

Explanation:

Conceptual analysis

Weight is the force with which a body is attracted due to the action of gravity and is calculated using the following formula:

W = m × g Formula (1)

W: weight

m: mass

g: acceleration due to gravity

The mass of a body on the moon is equal to the mass of a body on the earth

The acceleration due to gravity on a body is different on the moon and on the earth

Equivalences

1 slug = 14.59 kg

Known data

m_{earth} = m_{moon} = 250 * 10^3 slug = 250* 10^3slug * \frac{14.59kg}{1slug} = 3647.5* 10^3 kg

g_{moon}= 1.62 \frac{m}{s^2}

g_{earth}= 9.8 \frac{m}{s^2}

Problem development

To calculate the weight of the rocket on the moon and on earth we replace the data in formula (1):

W_{earth} = 3647.5* 10^3 kg * 9.8 \frac{m}{s^2} = 35.74 * 10^6 N : Rocket weight on earth

W_{moon} = 3647.5* 10^3 kg * 1.62 \frac{m}{s^2} = 5.91 * 10^6 N : Rocket weight on moon

7 0
4 years ago
I WILL MARK U BRAINLIEST IF U ANSWER THIS QUESTION! NEED IT ASAP PLS
Anuta_ua [19.1K]
  1. One common use of a convex mirror is as shaving mirror.
  2. One common use of convex mirror is as rear-view mirrors in automobiles vehicles.

<h3>What is a concave mirror?</h3>

A concave mirror is also referred to as a converging mirror and it can be defined as a type of mirror that is designed and developed with a reflective surface that is typically curved inward and away from the source of light.

Basically, one common use of a convex mirror include the following:

  • Shaving mirrors
  • Searchlights
  • Dental mirrors.

<h3>What is a convex mirror?</h3>

A convex mirror is also referred to as a diverging mirror and it can be defined as a type of mirror that is designed and developed with a reflective surface that typically bulges outward toward the source of light.

Basically, one common use of convex mirror is as rear-view mirrors in automobiles vehicles.

Read more on convex mirror here: brainly.com/question/24175067

#SPJ1

8 0
2 years ago
Suppose you have 600.0 grams of room temperature water (20.0 degrees Celsius) in a thermos. You drop 90.0 grams of ice at 0.00 d
IrinaK [193]

Answer:

T_{f} = 7.02 ° C

Explanation:

The liquid water gives heat to melt the ice (Q₁) maintaining the temperature of 0 ° C and then the two waters are equilibrated to a final temperature.

Let's start by calculating the heat needed to melt the ice

Q₁ = m L

Q₁ = 0.090 3.33 10⁵

Q₁ = 2997 10⁴ J

This is the heat needed to melt all the ice

Now let's calculate at what temperature the water reaches when it releases this heat

Q = M c_{e} (T₀ -T_{f})

Q₁ = Q

    T_{f} = T₀ - Q₁ / M c_{e}

T_{f} = 20.0 - 2997 104 / (0.600 4186)

T_{f}= 20.0 - 11.93

T_{f} = 8.07 ° C

This is the temperature of the water when all the ice is melted

Now the two bodies of water exchange heat until they reach an equilibrium temperature

Temperatures are

Water of greater mass     T₀₂ = 8.07ºC

Melted ice                         T₀₁ = 0ºC

M c_{e} (T₀₂ - T_{f}) = m c_{e} (T_{f} - T₀₁)

      M T₀₂ + m T₀₁ = m T_{f}+ M T_{f}

T_{f}= (M T₀₂ + 0) / (m + M)

T_{f} = M / (m + M) T₀₂

let's calculate

T_{f} = 0.600 / (0.600 + 0.090) 8.07

     T_{f} = 7.02 ° C

4 0
3 years ago
Star A and Star B have measured stellar parallax of 1.0 arc second and 0.75 arc second, respectively. Which star is closer? How
zhuklara [117]

Answer:

Star A is closer than Star B

Explanation:

As we know that in parallax method of distance measurement the angle subtended by the star when it covers a distance of one Parsec arc length, it is known as parallax angle

Here we can say

angle = \frac{1 Parsec}{distance}

so we have

distance = \frac{1 Parsec}{angle}

so here we have

angle subtended by Star A = 1 arc sec

angle subtended by star B = 0.75 arc sec

now we have

distance for star A is given as

d_a = \frac{1 Parsec}{1} = 1 Parsec

distance of star B is given as

d_b = \frac{1 Parsec}{0.75} = 1.33 Parsec

So star A is closer than star B

7 0
3 years ago
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