Answer:
1.24 × 10³ kPa
Explanation:
Step 1: Given data
- Initial pressure of the gas (P₁): 34.5 kPa
- Initial volume of the can (V₁): 473 mL
- Final pressure of the gas (P₂): ?
- Final volume of the can (V₂): 13.16 mL
Step 2: Calculate the final pressure of the gas in the can
If we assume that the gas in the can behaves as an ideal gas and that the temperature remains constant, we can calculate the final pressure of the gas using Boyle's law.
P₁ × V₁ = P₂ × V₂
P₂ = P₁ × V₁ / V₂
P₂ = 34.5 kPa × 473 mL / 13.16 mL = 1.24 × 10³ kPa
Answer:Re3(PO4)2 I think I'm wrong
Explanation:
Answer:
I believe it's false because the atomic number is the number of protons in the nucleus of an atom.
It is given that the person weighs 62 kg = 62,000 g
Natural abundances in mass percent are:
O = 65%
C = 18%
H = 10%
N = 3.0%
Ca = 1.6%
P = 1.2%
Corresponding weights of the elements are:
O = 65/100 * 62000 g = 40.30 * 10^3 g
C = 18/100 * 62000 g = 11.16 * 10^3 g
H = 10/100 * 62000 g = 62.00 * 10^2 g
N = 3.0/100 * 62000 g = 18.60 * 10^2 g
Ca = 1.6/100 * 62000 g = 9.92 * 10^2 g
P = 1.2/100 * 62000 g = 7.44 * 10^2 g
