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vladimir2022 [97]
2 years ago
7

A recipe requires 1/2 cup of milk for each 1/4 cup of water. How many cups of water are needed for each

Mathematics
1 answer:
aliina [53]2 years ago
5 0

Answer:

7

Step-by-step explanation:

You might be interested in
How to do a k over 8 equals 7
11Alexandr11 [23.1K]
Let's deconstruct the equation.

K x (1/8) = 7

You want to isolate K, so you multiply by 8 for both sides (since 8 x 1/8 = 1)
So, K = 7 x 8

K=56
6 0
3 years ago
what algorithm (rule) will produce the correct result for the sum "a+b" where a and b each represent any rational number.
Leokris [45]

Answer:

To find the sum of  a + b where a and b are rational number.

1. when a and b are natural numbers

just add them . for example a =3, b=8

then ,a + b = 11

2. When a and b  are whole numbers,

simply add them . for example a= 0, b=8

a+ b = 0 + 8= 8

3. When  a and b are integers

for example, a =-1 b=8,

a+ b= -1+ 8 =7,

a=-2, b= -8

a+ b= -2-8=-10

a= -6 , b=2

a+ b= -6 + 2= -4

a= 8, b= -2

a+ b= 8 +(-2) =6

I have written this because Rational number = [Integers{Whole number(Natural number)}]

now when a= Any fraction=\frac{p}{q} and b = Any fraction=\frac{u}{v}

now ,

\frac{p}{q} + \frac{u}{v}

Find L.C.M of q and v

= if q and v are Co-prime , just multiply them to find their  L.C.M.

For example 14,9. LCM=14×9=126

Otherwise, Find factors of q and v . Then take out common factors first and then multiply the remaining with with common factors.For example

q=12 and v=18

12 =2×2×3

18=2×3×3

common factor =2,3

non common=2,3

L.C.M= 2×2×3×3=36

Suppose LCM of q and v = r

then ,\frac{p}{q} + \frac{u}{v}

=\frac{{\frac{r}{q}}\times p+{\frac{r}{v}\times u}}{r}\\

= {{\frac{r}{q}}\times p+{\frac{r}{v}\times u}} = k

then ,

a + b=\frac{k}{r}





5 0
3 years ago
Extra points help me please
podryga [215]

Answer:

b

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
I need help with this question.
Vanyuwa [196]

Answer:

BGR=2

You can DM me for the explanation

7 0
3 years ago
Solve each given equation and show your work. Tell whether it has one solution, an infinite number of solutions, or no solutions
Bingel [31]

These are three equations and three answers.


Answers:

  • A) infinite solutions, identity
  • B) one solution, x = 27, neither contradiction nor identiy
  • C) x = no solutions, contradiction

Explanation:


Equation A: 20 - 4x = 12 - x + 8 - 3x

The objective is clearing the unknown, which is to isolate it in one side of the equation.

These are the steps and properties that you need to use:


1.  Combine like terms on right side:

20 - 4x  = 20 - 4x


2. Use addition property of equality (add 4x on each side).

20 = 20 ↔ identity


Conclusion: you have gotten a condition that is always true, no matter the value of x, which means that the equation has infinite solutions and it is an identity.


Equation B: 5x + 4x - 3  =  24 + 8x (note that I placed the equal sign as it was missing)


1.  Combine like terms on each side:

9x - 3 = 24 + 8x


2. Subtraction property and addition propertiy of equality (subtract 8x and add + 3 on both sides)

x = 27 ↔ solution (neither contradiction nor identity)


Conclusion: the solution is x = 27.


Equation C: 5x + 6 = 2x + 6 + 3x - 15 (note that I placed the equal signs as it was missing)


1. Comitne like terms on the right side:

5x + 6 = 5x - 9


2. Subtraction property of equality (subtract 5x from each side)


6 = - 9 ↔ contradiction


Conclusion: the equation does not have a solution since the final equality is always false (a condradiction or absurd).


For your information, when the variable (x) dissapears and fhe final equality is always true (for example 0 = 0, or 20 = 20), the equation is an identity.

6 0
3 years ago
Read 2 more answers
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