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tankabanditka [31]

3 years ago

15

PLEASE ANSWER MY QUESTION

2 answers:

Andrew [12]3 years ago

8 0

Answer:

a) 4

b) 5

c) 2s

d) 10 m/s

e) 5-10m/s^2

want to zøom?

In-s [12.5K]3 years ago

5 0

Answer:C 4:8 yw have a nice day

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A nonconducting ring of radius R is uniformly charged with a total positive charge q. The ring rotates at a constant angular spe

kipiarov [429]

The magnitude of the magnetic field on the axis of the ring (1/2)R from its center is [ μ₀ ωqR² ] / [2.5(√5)πR ].

The magnetic influence on moving electric currents, electric charges, and magnetic materials is described by a magnetic field, which is a vector field. When a charge moves through a magnetic field, a force that is perpendicular to both its own velocity and the magnetic field operates on it.

The radius of the nonconducting ring is R.

The ring is uniformly charged q.

The angular speed of the ring is ω.

The ring is x = (1/2)R from the center of the ring.

The magnetic field on the axis of a current loop is given as:

B = [ μ₀ IR² ] / [4π(x² + R²)^{3/2} ]

Now, I = q / [2π/ω]

When x = R/2 the magnitude of the magnetic field is:

B = [ μ₀ ωqR² ] / [4π( x² + R²)^{3/2} ]

B = [ μ₀ ωqR² ] / [4π( ( R/2 )² + R² )^{3/2} ]

B = [ μ₀ ωqR² ] / [4π( [5/4]R² )^{3/2} ]

B = [ μ₀ ωqR² ] / [2.5(√5)πR ]

Learn more about the magnetic field here:

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6 0

2 years ago

A soccer ball is kicked horizontally off a bridge with a heigh of 36m. The ball travels 25m horizontally before it hits the pave

kow [346]

Answer:

The initial velocity was U=22.14m/s

Explanation:

Step one :

Applying the third equation of motion

v² = u²+ 2as

Where v= Final velocity

U =initial velocity

a= acceleration due to gravity

S= distance or displacement

Step two :

V= 0

a= 9.81m/s²

S=25m

U=?

Step three :

Substituting into the equation we have

0²=U²+2*9.81*25

0=U²+490.5

U²=-490.5

U=√490.5

U=22.14m/s

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4 years ago

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Kazeer [188]

If this is an English Question list the terms so we can pick from those. Otherwise we dont have the correct terms to answer the question

7 0

3 years ago

Two objects are moving at equal speed along a level, frictionless surface. the second object has twice the mass of the first obj

Zarrin [17]

first object gors highest

second object goes lowest.

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3 years ago

Two uniform bars of the same dimensions are constructed from the same material. One bar has five evenly spaced holes through it

Elan Coil [88]

Solution :

The angular acceleration, $\alpha$ is obtained from the equation of the $\text{Newton's second law}$ of rotational motion,

Thus,

$\tau = F \times d$

or $\tau = I \times \alpha$

where $\tau$ is torque, F is force, d is moment arm distance, I is the moment of inertia

Thus, $\alpha=\frac{(F\times d)}{I}$

Now if the force and the moment arm distance are constant, then the $\text{angular acceleration is inversely proportional to the moment of inertia.}$

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Therefore, the bar in case (1), has less moment of inertia and a greater angular acceleration.

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3 years ago