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zhannawk [14.2K]
3 years ago
6

If a home uses a large supply of solar panels to generate electricity, but has no battery system, surplus electricity that is pr

oduced is usually __________.
Physics
1 answer:
Alinara [238K]3 years ago
4 0

Answer:

Passed into the power grid for others to use the electricity

Explanation:

If a home uses a large supply of solar panels to generate electricity, but has no battery system, surplus electricity that is produced is usually passed into the power grid for others to use the electricity, generating a income to the homeowner

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A 0.145 kg baseball is flying at a height of 2.50 m. How much potential energy
Studentka2010 [4]

Gravitational potential energy is the energy stored in an object as the result of its vertical position or height. It can be calculated as its weight times the height. This is:

\boxed{U_g=W\cdot h=mgh}

Where:

  • W is the weight of the object
  • m is the mass
  • g is gravitational acceleration
  • h is the height

Evaluating:

U_g = (0.145\;kg)(9.8\;m/s^2)(2.50\;m)\\\\\boxed{U_g=3.5525\;J}

R/ The ball has 3.5525 J of potential energy.

3 0
3 years ago
If a car has traveled 24 km in 2 hours, what is its average speed?
PIT_PIT [208]

Answer:

12km per hour

Explanation:

The formula is distance/time.

24km/2 hours = 12km/1 hour

3 0
3 years ago
Read 2 more answers
A rolling ball has an initial velocity of 5 meters per second. 30 seconds later, its velocity it 2 meters per second. What is th
sergeinik [125]
The answer is -0.2 hope this helps. :)
5 0
3 years ago
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A cart loaded with bricks has a total mass of 28.3 kg and is pulled at constant speed by a rope. The rope is inclined at 23.1◦ a
seropon [69]

Answer:

Explanation:

Given

mass  of cart with bricks m=28.3\ kg

inclination \theta =23.1^{\circ}

distance moved s=28.7\ m

coefficient of kinetic friction \mu _k=0.2

it is given that cart is moving with constant velocity so net force on it is Zero

if T is the tension in rope

Net normal Reaction

N=mg-T\sin \theta

Friction force f_r=\mu _k\cdot N

f_r=\mu _k(mg-T\sin \theta )

Horizontal force =T\cos \theta

therefore    

T\cos \theta =\mu _k(mg-T\sin \theta )

T=\frac{\mu _kmg}{\cos \theta +\mu_k\sin \theta }

T=\frac{55.468}{0.9982}

T=55.56\ N

work done W=T\cos \theta \cdot s

W=55.56\cos (23.1)\cdot 28.7

W=1466.93\ J                            

6 0
3 years ago
An electric iron is labeled 1000W. How many Joule of energy is consumed if it is used for one hour?​
cupoosta [38]

Answer:1kwh

Explanation:E=PT

E=1000w(3600s)

E=1kwh

4 0
2 years ago
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