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77julia77 [94]
4 years ago
8

List some non-examples of Convection​

Chemistry
1 answer:
dimulka [17.4K]4 years ago
7 0

Non Example: It is not convection because heat is not transferred through a fluid (gas or liquid).

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There are 81 amino acid residues in the precursor molecule of bovine insulin. What is the least number of bases that must be in
Usimov [2.4K]
If you count the methionine expressed for the start codon as part of the precursor protein, then (81+1)*3. (The start codon is expressed, but the stop codon isn't.) 
8 0
4 years ago
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A student mixes in a test tube 3.00mL of 0.050M CuSO4with 7.00mL of 0.20M NH3/NH41 . The solution becomes a deep blue color. Ass
valkas [14]

Answer:

\large \boxed{\text{0.0035 mol/L}}

Explanation:

We are given the volumes and concentrations of two reactants, so this is a limiting reactant problem.

We know that we will need moles, so, lets assemble all the data in one place.

                   Cu²⁺ + 4NH₃ ⟶ Cu(NH₃)₄²⁺

    V/mL:   3.00      7.00

c/mol·L⁻¹:  0.050   0.20

1. Identify the limiting reactant

(a) Calculate the moles of each reactant  

\text{Moles of Cu}^{2+}= \text{3.00 mL solution} \times \dfrac{\text{0.050 mmol Cu}^{2+}}{\text{1 mL solution}} = \text{0.150 mmol Cu}^{2+}\\\\\text{Moles of NH}_{3} = \text{7.00 mL solution} \times \dfrac{\text{0.20 mmol NH}_{3}}{\text{1 mL solution}} = \text{0.140 mmol NH}_{3}

(b) Calculate the moles of Cu(NH₃)₄²⁺ that can be formed from each reactant

(i) From Cu²⁺

\text{Moles of Cu(NH$_{3}$)$_{4}$$^{2+}$} = \text{0.150 mmol Cu}^{2+} \times \dfrac{\text{1 mmol Cu(NH$_{3}$)$_{4}$$^{2+}$}}{\text{1 mmol Cu}^{2+}}\\\\= \text{0.150 mmol Cu(NH$_{3}$)$_{4}$$^{2+}$}

(ii) From NH₃

\text{Moles of Cu(NH$_{3}$)$_{4}$$^{2+}$} = \text{0.140 mmol NH}_{3} \times \dfrac{\text{1 mmol Cu(NH$_{3}$)$_{4}$$^{2+}$}}{\text{4 mmol NH}_{3}}\\\\= \text{0.0350 mmol Cu(NH$_{3}$)$_{4}$$^{2+}$}

NH₃ is the limiting reactant, because it forms fewer moles of the complex ion.

(c) Concentration of the complex ion

\text{The reaction forms 0.0350 mmol Cu(NH$_{3}$)$_{4}$$^{2+}$ in a total volume of 10.00 mL.}\\c = \dfrac{\text{moles}}{\text{litres}} = \dfrac{\text{0.0350 mmol}}{\text{10.00 mL}} = \textbf{0.0035 mol/L}\\\\\text{The concentration of the complex ion is $\large \boxed{\textbf{0.0035 mol/L}}$}

7 0
3 years ago
Select the correct answer.
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C. Ninhydrin is used to detect prints on a non-porous surface
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3 years ago
Explain how electron microscopes work and why some scientists might prefer to use electron microscopes instead of light microsco
WINSTONCH [101]

Answer:

Electron microscopes differ from light microscopes in that they produce an image of a specimen by using a beam of electrons rather than a beam of light. Electrons have much a shorter wavelength than visible light, and this allows electron microscopes to produce higher-resolution images than standard light microscopes.

Explanation:

8 0
3 years ago
The first energy shell around a nucleus can hold _______ electrons. The second energy shell can hold ________.
Bond [772]

Hi there,

I hope you and your family are staying safe and healthy!

The correct answer is C

Each shell can contain only a fixed number of electrons. The first energy shell around a nucleus can hold up to 2 electrons. Then the second shell can hold up to 8 eletrcons.

Please leave 5 stars and a like if you find this answer helpful!

Best,

~Gary

4 0
2 years ago
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