<h3>Answers are:
sine, tangent, cosecant, cotangent</h3>
Explanation:
On the unit circle we have some point (x,y) such that x = cos(theta) and y = sin(theta). The sine corresponds to the y coordinate of the point on the circle. Quadrant IV is below the x axis which explains why sine is negative here, since y < 0 here.
Since sine is negative, so is cosecant as this is the reciprocal of sine
csc = 1/sin
In quadrant IV, cosine is positive as x > 0 here. So the ratio tan = sin/cos is going to be negative. We have a negative over a positive when we divide.
Because tangent is negative, so is cotangent.
The only positive functions in Q4 are cosine and secant, which is because sec = 1/cos.
Answer:
Answer is q = 2
Step-by-step explanation:
First make the equation with a constant so p=k/q
then substitute q to 6 and p to 23.
Then you have 23=k/6 and to find k multiply both sides to get k=138
next substitute p as 69=138/q then multiply q on both sides to get 69xq=138 and then divide 69 to 138 go get q which is 2
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Answer:
3 over5 multiplied by 320 equals 192
