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ladessa [460]
3 years ago
14

A solution is made by mixing 124. g of acetyl bromide (CH COBI and 119. g of chloroform (CHCI3) Calculate the mole fraction of a

cetyl bromide in this solution. Round your answer to 3 significant digits.
Chemistry
1 answer:
vampirchik [111]3 years ago
5 0

Answer : The mole fraction of acetyl bromide in this solution is, 0.503

Explanation :  Given,

Mass of C_2H_3BrO = 124 g

Molar mass of C_2H_3BrO = 122.95 g/mole

Mass of CHCl_3 = 119 g

Molar mass of CHCl_3 = 119.38 g/mole

First we have to calculate the moles of C_2H_3BrO and CHCl_3.

\text{Moles of }C_2H_3BrO=\frac{\text{Mass of }C_2H_3BrO}{\text{Molar mass of }C_2H_3BrO}=\frac{124g}{122.95g/mole}=1.008moles

\text{Moles of }CHCl_3=\frac{\text{Mass of }CHCl_3}{\text{Molar mass of }CHCl_3}=\frac{119}{119.38g/mole}=0.997moles

Now we have to calculate the mole fraction of C_2H_3BrO and CHCl_3.

\text{Mole fraction of }C_2H_3BrO=\frac{\text{Moles of }C_2H_3BrO}{\text{Moles of }C_2H_3BrO+\text{Moles of }CHCl_3}

\text{Mole fraction of }C_2H_3BrO=\frac{1.008}{1.008+0.997}=0.503

and,

\text{Mole fraction of }CHCl_3=\frac{\text{Moles of }CHCl_3}{\text{Moles of }C_2H_3BrO+\text{Moles of }CHCl_3}

\text{Mole fraction of }CHCl_3=\frac{0.997}{1.008+0.997}=0.497

Therefore, the mole fraction of acetyl bromide in this solution is, 0.503

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According to our textbook, write the formula for the anhydrous compound that was part of the mixture called natron that was used
bearhunter [10]

Answer:

The formula for the anhydrous compound that was part of the mixture called natron that was used by the Egyptians is Na2(CO3)10(H2O).

They use this compound for medicine, cookery, agriculture, in glass-making and to dehydrate egyptian mummies.

Compound of sodium carbonate and sodium bicarbonate was the name of the resulting hydrate that formed.

8 0
3 years ago
In the reaction Ca + Cl2 → CaCl2, what is the mole ratio of chlorine to calcium chloride?
Anit [1.1K]

Answer:

D. 1:1

Explanation:

For every 1 mole of chlorine (Cl₂), there is one mole of calcium chloride (CaCl₂).

So, the mole ratio of chlorine to calcium chloride is 1:1.

Hope this helps. :)

6 0
3 years ago
Read 2 more answers
In a percentage composition investigation a compound was decomposed into its elements: 20.0 g of calcium, 6.0 g of carbon, and 2
inysia [295]

The percentage composition of this compound : 40%Ca, 12%C and 48%O

<h3>Further explanation</h3>

Given

20.0 g of calcium,

6.0 g of carbon,

and 24.0 g of oxygen.

Required

The percentage composition

Solution

Total mass of compound :

=mass calcium + mass carbon + mass oxygen

=20 g + 6 g + 24 g

=50 g

Percentage composition :

  • Ca-calcium

\tt \dfrac{20}{50}\times 100\%=40\%

  • C-carbon

\tt \dfrac{6}{50}\times 100\%=12\%

  • O-oxygen

\tt \dfrac{24}{50}\times 100\%=48\%

3 0
2 years ago
A solution of barium nitrate has 61.2g of barium nitrate in 1 liter of solution. How many mg of barium are there in 7.5 quarts
Nuetrik [128]

Answer:

220.44g Ba²⁺ ions in solution

Explanation:

Given parameters:

Mass of barium nitrate = 61.2g

Volume of solution = 1 liter

Unkown:

Mass of barium in 7.5quarts of solution?

Solution

We must first convert quarts to its liter equivalence:

                    1 quarts = 0.95 liter

                   7.5 quarts = 0.95 x 7.5; 7.125liter

Now, let us find the mass of barium nitrate in a solution of 7.125liter:

        Given:

            1 liter of solution contains 61.2g of barium nitrate:

          7.125 liter will contain  7.125 x 61.2 = 436.05g of barium nitrate.

The formula of the compound is Ba(NO₃)₂:

  In solution we have  Ba²⁺ + NO₃⁻

                Ba(NO₃)₂ → Ba²⁺ + 2NO₃⁻

 

Number of moles of Ba(NO₃)₂ = \frac{mass of Ba(NO₃)₂}{Molar mass of Ba(NO₃)₂}

Molar mass of Ba(NO₃)₂ = 137 + 2[14 + 3(16)] = 271g/mol

Number of moles of Ba(NO₃)₂ = \frac{436.05}{271} = 1.609mole

      1 mole of Ba(NO₃)₂ will produce 1 mole of Ba²⁺ ions in solution

    therefore, 1.609mole of Ba(NO₃)₂ will also yield 1.609mole of Ba²⁺ ions in solution

Mass of Ba²⁺ ions = Number of moles of Ba²⁺ ions  x molar mass of Ba²⁺ ions

Mass of Ba²⁺ ions = 1.609 x 137 = 220.44g

3 0
3 years ago
Ozone depleting chemicals are MOST
mina [271]

Ozone depleting chemicals are most likely belong to <u>halogen </u>group on the periodic table.

<h3>Ozone depleting chemicals are most likely to belong to which group on the periodic table?</h3>

Ozone depleting chemicals are the halogen group on the periodic table. Chlorofluorocarbons (CFCs), hydrochlorofluorocarbons (HCFCs), halons, methyl bromide, carbon tetrachloride, hydrobromo-fluorocarbons and methyl chloroform. Fluorine, chlorine, bromine, iodine, astatine and tennessine are the elements of halogen group elements. These elements greatly affected the ozone layer.

So we can conclude that Ozone depleting chemicals are most likely belong to halogen group on the periodic table.

Learn more about ozone here: brainly.com/question/5019112

#SPJ1

3 0
1 year ago
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