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iris [78.8K]
3 years ago
14

Consider the balanced equation below. 4NH3 + 3O2 --> 2N2 + 6H2O What is the mole ratio of NH3 to N2?

Chemistry
2 answers:
grandymaker [24]3 years ago
5 0

Answer : The mole ratio of NH_3:N_2 is, 2 : 1

Explanation :

As we are given the balanced chemical reaction. Now we have to determine the mole ratio of NH_3\text{ to }N_2

The given balanced chemical reaction is,

4NH_3+3O_2\rightarrow 2N_2+6H_2O

By the stoichiometry we can say that, 4 moles of ammonia (NH_3) react with 3 moles of oxygen gas (O_2) to give 2 moles of nitrogen gas (N_2) and 6 moles of water (H_2O).

From this we conclude that,

The mole ratio of NH_3:N_2 is, 4 : 2 or, 2 : 1

Therefore, the mole ratio of NH_3:N_2 is, 2 : 1

AURORKA [14]3 years ago
4 0
The balanced equation given is:
4NH3 + 3O2 .....> 2N2 + 6H2O

From this equation, we can note that 4 moles of NH3 are required to produce 2 moles of N2.

Therefore, the mole ratio of NH3 to N2 is 4:2 which can be simplified into 2:1
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Consider the data presented below. time (s) 0 40 80 120 160 moles of a 0.100 0.067 0.045 0.030 0.020 part a part complete determ
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the data is as follows 
time         0         40        80       120       160
moles    0.100   0.067  0.045    0.030    0.020


Q1)
for the first 40 s change of moles ;
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      = - (0.067-0.100)/40s
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for the next 40 s
      = -(0.045-0.067)/40
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the 40 s after that
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and A is the only reactant that affects the rate of the reaction

rate = k [A]ᵇ
8.25 × 10⁻⁴ mol/s = k [0.100 mol]ᵇ ----1
5.5 x 10⁻⁴ mol/s = k [0.067 mol]ᵇ   -----2
divide the 2nd equation by the 1st equation
1.5 = [1.49]ᵇ
b is almost equal to 1
Therefore this is a first order reaction

Q2)
to find out the rate constant(k), we have to first state the equation for a first order reaction.
rate = k[A]ᵇ
As A is the only reactant thats considered for the rate equation. 
Since this is a first order reaction,
b = 1
therefore the reaction is 
rate = k[A]
substituting the values,
8.25 x 10⁻⁴ mol/s = k [0.100 mol]
k = 8.25 x 10⁻⁴ mol/s /0.100mol
   = 8.25 x 10⁻³ s⁻¹

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