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Gwar [14]
2 years ago
14

Laboratory work often involves making dilutions of standard solutions. Dilution problems are not hard, but they can sure get you

confused if you aren't careful. The following relation can often save you from pulling all of your hair out:
C1V1= C2V2
Where,

V1 = initial volume
C1 = initial concentration
V2 final volume
C2= final concentration

A 0.6M solution of NaOH is diluted from 100 ml to 1liter. What is the new NAOH concentration?
Chemistry
1 answer:
Paladinen [302]2 years ago
6 0

Answer:

0.06M

Explanation:

Using the formula as outlined in this question,

C1V1= C2V2

Where;

V1 = initial volume (Litres)

C1 = initial concentration (M)

V2 = final volume (Litres)

C2 = final concentration (M)

According to the information provided on NaOH in this question, V1 = 100mL = 100/1000 = 0.1 L, V2 = 1L, C1 = 0.6M, C2 = ?

C1V1= C2V2

0.6 × 0.1 = C2 × 1

0.06 = C2

C2 = 0.06M

The new concentration of NaOH is 0.06M.

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How much ice at a temperature of -17.5 ∘C must be dropped into the water so that the final temperature of the system will be 31.
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Answer:

An insulated beaker with negligible mass contains liquid water with a mass of 0.205kg and a temperature of 79.9 °C How much ice at a temperature of −17.5 °C must be dropped into the water so that the final temperature of the system will be 31.0 °C? Take the specific heat for liquid water to be 4190J/Kg.K, the specific heat for ice to be 2100J/Kg.K, and the heat of fusion for water to be 334000J/kg.

The answer to the above question is

Therefore 0.1133 kg  ice at a temperature of -17.5 ∘C must be dropped into the water so that the final temperature of the system will be 31.0 °C

Explanation:

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