Answer:
the Mercury planet is likely to have life but the earth as a lot of oxygen
Answer:
Correct option is answer a) SCl2
Answer:
An insulated beaker with negligible mass contains liquid water with a mass of 0.205kg and a temperature of 79.9 °C How much ice at a temperature of −17.5 °C must be dropped into the water so that the final temperature of the system will be 31.0 °C? Take the specific heat for liquid water to be 4190J/Kg.K, the specific heat for ice to be 2100J/Kg.K, and the heat of fusion for water to be 334000J/kg.
The answer to the above question is
Therefore 0.1133 kg ice at a temperature of -17.5 ∘C must be dropped into the water so that the final temperature of the system will be 31.0 °C
Explanation:
To solve this we proceed by finding the heat reaquired to raise the temperature of the water to 31.0 C from 79.9 C then we use tht to calculate for the mass of ice as follows
ΔH = m×c×ΔT
= 0.205×4190×(79.9 -31.0) = 42002.655 J
Therefore fore the ice, we have
Total heat = mi×L + mi×ci×ΔTi = mi×334000 + mi × 2100 × (0 -−17.5) = 42002.655 J
370750×mi = 42002.655 J
or mi = 0.1133 kg
Therefore 0.1133 kg ice at a temperature of -17.5 ∘C must be dropped into the water so that the final temperature of the system will be 31.0 °C
Answer:
11 L
Explanation:
Work-done = P (V₂ - V₁)--------------------------------------- (1)
P= 650 torr
= 86659.5 N/m²
V₁=40 cm³
= 40 x 10⁻⁶ m³
V₂ = ?
Workdone =950 J
Substituting into equation (1)
950 = 86659.5 ( V₂- 40 x 10⁻⁶ )
V₂= (950/86659.5) + 40 x 10⁻⁶
= 0.01096 + 40 x 10⁻⁶
= 0.011 m³
= 11 L
Answer:
They all contain 8 protons but, the number of neutrons increase by 1.
Explanation: