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BabaBlast [244]
3 years ago
9

Consider a mixture of air and gasoline vapor in

Chemistry
1 answer:
maria [59]3 years ago
3 0

Answer:

11 L

Explanation:

Work-done = P (V₂ - V₁)--------------------------------------- (1)

P= 650 torr

 =  86659.5 N/m²

V₁=40 cm³

   = 40 x 10⁻⁶  m³

V₂ = ?

Workdone =950 J

Substituting into equation (1)

950 =  86659.5 ( V₂- 40 x 10⁻⁶ )

V₂= (950/86659.5) + 40 x 10⁻⁶

    = 0.01096 + 40 x 10⁻⁶

    = 0.011 ‬m³

    = 11 L

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